Haloalkanes primarily undergo nucleophilic substitution reactions due to the presence of a good leaving group (halogen).

Citric acid is used as a preservative, flavoring agent, and cleaning agent.

The major product is But-2-ene due to the more stable double bond formed during elimination.

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol. Mass = moles x molar mass = 3 moles x 58.5 g/mol = 174 g.

The molar mass of NaCl is 58.5 g/mol. Therefore, 3 moles of NaCl weigh 3 x 58.5 g = 175.5 g.

Molar mass of NaOH = 40 g/mol; grams = moles × molar mass = (1 mole/L × 0.5 L) × 40 g/mol = 20 g

Molar mass of NaCl = 58.44 g/mol; mass = moles × molar mass = 3 moles × 58.44 g/mol = 175.32 g

Mass = moles × molar mass = (0.1 moles/L × 1 L) × 58.5 g/mol = 5.85 g.

Molar mass of NaOH = 40 g/mol. Mass = moles × molar mass = 0.5 moles × 40 g/mol = 20 g.

Area = 1/2 * base * height = 1/2 * 10 * x. Max area occurs when x = 10, giving Area = 50.

The d subshell can hold a maximum of 10 electrons.

The f-subshell can hold a maximum of 14 electrons.

The maximum number of electrons in a shell is given by the formula 2n². For n=3, it is 2(3)² = 18.

The maximum number of electrons in a shell is given by the formula 2n². For n=3, it is 2(3)² = 18.

Phosphorus can exhibit a maximum oxidation state of +5 in compounds like PCl5.

The maximum profit occurs at x = -b/(2a) = 10/2 = 5. P(5) = -5^2 + 10*5 - 16 = 9.

The vertex occurs at x = 2. f(2) = -2^2 + 4(2) + 1 = 5.

The vertex occurs at x = 3. f(3) = -9 + 18 - 8 = 1.

The vertex occurs at x = 2. f(2) = 3(2^2) - 12(2) + 9 = 0.

The vertex form gives the minimum at x = 2. f(2) = 2.

The vertex occurs at x = 2. f(2) = 2.

The vertex form gives the minimum at x = 3. f(3) = 3^2 - 6(3) + 10 = 1.

The vertex occurs at x = 2. f(2) = 4(2^2) - 16(2) + 20 = 4.

The modulus is calculated as √(3^2 + 4^2) = √(9 + 16) = √25 = 5.

Molality (m) = moles of solute / kg of solvent = 10 moles / 5 kg = 2 m.

The molar mass of water is calculated as follows: H (1 g/mol) x 2 + O (16 g/mol) = 2 + 16 = 18 g/mol.

Molarity (M) = moles of solute / liters of solution = 5 moles / 2 L = 2.5 M.

Molarity (M) = moles of solute / liters of solution. Moles of NaCl = 58.5 g / 58.5 g/mol = 1 mol. Therefore, M = 1 mol / 1 L = 1 M.

Molarity (M) = moles of solute / liters of solution. Moles of NaCl = 5 g / 58.5 g/mol = 0.0855 moles. Volume of solution = 250 mL = 0.250 L. M = 0.0855 moles / 0.250 L = 0.342 M, approximately 0.34 M.

The molecular formula of Benzoic acid is C7H6O2.