MHT-CET
Q. A cyclist does 600 J of work to climb a hill. If he takes 30 seconds, what is his average power output? (2022)
A.
10 W
B.
20 W
C.
30 W
D.
40 W
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Solution
Power = Work / Time = 600 J / 30 s = 20 W.
Correct Answer: B — 20 W
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Q. A cyclist travels at a speed of 10 m/s for 5 seconds. What distance does he cover? (2023)
A.
25 m
B.
50 m
C.
75 m
D.
100 m
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Solution
Distance = speed * time = 10 m/s * 5 s = 50 m.
Correct Answer: B — 50 m
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Q. A flywheel has a moment of inertia I and is rotating with an angular velocity ω. If a torque τ is applied, what is the angular acceleration? (2021)
A.
τ/I
B.
I/τ
C.
ω/τ
D.
Iω
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Solution
From Newton's second law for rotation, τ = Iα, thus α = τ/I.
Correct Answer: A — τ/I
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Q. A force of 10 N is applied to an object, causing it to accelerate at 2 m/s². What is the mass of the object? (2020)
A.
5 kg
B.
10 kg
C.
15 kg
D.
20 kg
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Solution
Using F = ma, mass m = F/a = 10 N / 2 m/s² = 5 kg.
Correct Answer: A — 5 kg
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Q. A force of 10 N is applied to move an object 5 m. What is the work done? (2023)
A.
50 J
B.
10 J
C.
5 J
D.
20 J
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Solution
Work done = Force × Distance = 10 N × 5 m = 50 J.
Correct Answer: A — 50 J
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Q. A force of 30 N is applied to a 6 kg object. What is the object's acceleration? (2023)
A.
3 m/s²
B.
4 m/s²
C.
5 m/s²
D.
6 m/s²
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Solution
Using F = ma, we find a = F/m = 30 N / 6 kg = 5 m/s².
Correct Answer: B — 4 m/s²
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Q. A force of 50 N is applied to move an object 4 m. How much work is done?
A.
100 J
B.
150 J
C.
200 J
D.
250 J
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Solution
Work = Force * Distance = 50 N * 4 m = 200 J.
Correct Answer: C — 200 J
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Q. A gas expands isothermally at 300 K and absorbs 600 J of heat. What is the work done by the gas? (2023)
A.
600 J
B.
300 J
C.
900 J
D.
0 J
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Solution
In an isothermal process, the work done by the gas is equal to the heat absorbed. Therefore, work done = 600 J.
Correct Answer: A — 600 J
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Q. A machine does 1200 J of work in 60 seconds. What is its efficiency if the input energy is 2000 J? (2022)
A.
60%
B.
70%
C.
80%
D.
90%
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Solution
Efficiency = (Output Work / Input Energy) * 100 = (1200 J / 2000 J) * 100 = 60%.
Correct Answer: A — 60%
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Q. A mass attached to a spring oscillates with a period of 2 seconds. What is its frequency? (2014)
A.
0.5 Hz
B.
1 Hz
C.
2 Hz
D.
4 Hz
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Solution
Frequency f = 1/T = 1/2 s = 0.5 Hz.
Correct Answer: A — 0.5 Hz
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Q. A mass-spring system oscillates with a frequency of 5 Hz. What is the angular frequency? (2021)
A.
10π rad/s
B.
5π rad/s
C.
2π rad/s
D.
20π rad/s
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Solution
Angular frequency ω = 2πf = 2π × 5 Hz = 10π rad/s.
Correct Answer: A — 10π rad/s
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Q. A parallel plate capacitor has a capacitance of 5 µF. If the potential difference across it is increased from 10 V to 20 V, what is the change in stored energy?
A.
25 µJ
B.
50 µJ
C.
75 µJ
D.
100 µJ
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Solution
Energy U = 1/2 C V^2. Initial U = 1/2 * 5 × 10^-6 * 10^2 = 0.025 J; Final U = 1/2 * 5 × 10^-6 * 20^2 = 0.1 J. Change = 0.1 - 0.025 = 0.075 J = 75 µJ.
Correct Answer: B — 50 µJ
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Q. A particle is moving in a circle of radius r with a constant speed v. What is the angular velocity? (2022)
A.
v/r
B.
r/v
C.
vr
D.
v²/r
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Solution
Angular velocity ω = v/r.
Correct Answer: A — v/r
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Q. A particle moves in a circular path of radius r with a constant speed v. What is the centripetal acceleration? (2022)
A.
v²/r
B.
vr
C.
r/v
D.
v/r
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Solution
Centripetal acceleration a_c = v²/r.
Correct Answer: A — v²/r
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Q. A pendulum completes 20 oscillations in 40 seconds. What is its frequency? (2022)
A.
0.5 Hz
B.
1 Hz
C.
2 Hz
D.
4 Hz
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Solution
Frequency f = number of oscillations / time = 20 / 40 s = 0.5 Hz.
Correct Answer: B — 1 Hz
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Q. A pendulum swings with a maximum angle of 30 degrees. What is the approximate time period for small angles? (2022)
A.
1.0 s
B.
0.5 s
C.
2.0 s
D.
0.25 s
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Solution
For small angles, T ≈ 2π√(L/g). Assuming L = 1 m, T ≈ 2π√(1/9.8) ≈ 2.0 s.
Correct Answer: A — 1.0 s
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Q. A person lifts a 10 kg box to a height of 2 m. What is the work done against gravity? (g = 9.8 m/s²)
A.
196 J
B.
98 J
C.
20 J
D.
10 J
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Solution
Work = mgh = 10 kg * 9.8 m/s² * 2 m = 196 J.
Correct Answer: A — 196 J
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Q. A rotating object has a moment of inertia I and an angular velocity ω. What is its rotational kinetic energy? (2020)
A.
(1/2)Iω
B.
(1/2)Iω²
C.
Iω²
D.
I/2ω²
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Solution
Rotational kinetic energy K.E. = (1/2)Iω².
Correct Answer: B — (1/2)Iω²
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Q. A simple pendulum has a length of 1 m. What is its time period? (2023)
A.
1.0 s
B.
2.0 s
C.
0.5 s
D.
0.25 s
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Solution
The time period T of a simple pendulum is given by T = 2π√(L/g). For L = 1 m and g = 9.8 m/s², T = 2π√(1/9.8) ≈ 2.0 s.
Correct Answer: A — 1.0 s
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Q. A solid cylinder rolls down an incline. If its height is h, what is its linear speed at the bottom? (2023)
A.
√(gh)
B.
√(2gh)
C.
√(3gh)
D.
√(4gh)
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Solution
Using conservation of energy, potential energy converts to kinetic energy. For a solid cylinder, v = √(2gh).
Correct Answer: B — √(2gh)
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Q. A solid sphere of radius R rolls without slipping down an incline of height h. What is its speed at the bottom of the incline? (2021)
A.
√(2gh)
B.
√(3gh)
C.
√(4gh)
D.
√(5gh)
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Solution
Using conservation of energy, potential energy at the top = kinetic energy at the bottom. For a solid sphere, v = √(5gh/7). Thus, speed at the bottom is √(3gh).
Correct Answer: B — √(3gh)
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Q. A sound wave travels through air at 343 m/s. If its frequency is 686 Hz, what is its wavelength? (2023)
A.
0.5 m
B.
1 m
C.
2 m
D.
3 m
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Solution
Wavelength λ = v/f = 343 m/s / 686 Hz = 0.5 m.
Correct Answer: A — 0.5 m
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Q. A stone is thrown horizontally from a height of 45 m. How long will it take to hit the ground? (Take g = 10 m/s²) (2023)
A.
3 s
B.
4.5 s
C.
5 s
D.
6 s
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Solution
Using h = 0.5 * g * t^2, we have 45 = 0.5 * 10 * t^2. Solving gives t^2 = 9, so t = 3 s.
Correct Answer: A — 3 s
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Q. A train moving at 72 km/h applies brakes and comes to a stop in 5 seconds. What is the deceleration? (2023)
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
First convert speed to m/s: 72 km/h = 20 m/s. Deceleration = (final velocity - initial velocity) / time = (0 - 20) / 5 = -4 m/s².
Correct Answer: C — 4 m/s²
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Q. A tuning fork produces a sound wave of frequency 440 Hz. What is the period of the wave? (2019)
A.
0.00227 s
B.
0.005 s
C.
0.01 s
D.
0.001 s
Show solution
Solution
Period T = 1/f = 1/440 Hz ≈ 0.00227 s.
Correct Answer: A — 0.00227 s
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Q. A tuning fork vibrates at a frequency of 440 Hz. What is the time period of the fork? (2020)
A.
0.00227 s
B.
0.0045 s
C.
0.01 s
D.
0.005 s
Show solution
Solution
Time period T = 1/f = 1/440 Hz ≈ 0.00227 s.
Correct Answer: A — 0.00227 s
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Q. A uniform rod of length L is pivoted at one end and released from rest. What is the angular speed just before it hits the ground? (2019)
A.
√(3g/L)
B.
√(2g/L)
C.
√(g/L)
D.
√(4g/L)
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Solution
Using conservation of energy, potential energy converts to rotational kinetic energy. Angular speed ω = √(3g/L).
Correct Answer: B — √(2g/L)
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Q. A vehicle travels with a uniform speed of 60 km/h. How far will it travel in 2 hours? (2023)
A.
80 km
B.
100 km
C.
120 km
D.
140 km
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Solution
Distance = speed * time = 60 km/h * 2 h = 120 km.
Correct Answer: C — 120 km
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Q. A wave has a frequency of 60 Hz and a wavelength of 3 m. What is its speed? (2016)
A.
180 m/s
B.
120 m/s
C.
60 m/s
D.
90 m/s
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Solution
Speed v = f × λ = 60 Hz × 3 m = 180 m/s.
Correct Answer: A — 180 m/s
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Q. A wave on a string has a speed of 50 m/s and a wavelength of 2 m. What is its frequency? (2018)
A.
25 Hz
B.
50 Hz
C.
100 Hz
D.
75 Hz
Show solution
Solution
Frequency f = v/λ = 50 m/s / 2 m = 25 Hz.
Correct Answer: A — 25 Hz
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