Physics Syllabus (JEE Main)
Q. A 10 kg object is dropped from a height. What is the force acting on it just before it hits the ground?
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A.
10 N
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B.
20 N
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C.
30 N
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D.
40 N
Solution
The force acting on the object is its weight, F = mg = 10 kg * 10 m/s² = 100 N.
Correct Answer: B — 20 N
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Q. A 10 kg object is hanging at rest from a rope. What is the tension in the rope?
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A.
0 N
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B.
10 N
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C.
100 N
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D.
50 N
Solution
The tension in the rope must balance the weight of the object. T = mg = 10 kg * 10 m/s² = 100 N.
Correct Answer: C — 100 N
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Q. A 10 kg object is hanging from a rope. What is the tension in the rope when the object is at rest?
-
A.
0 N
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B.
10 N
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C.
100 N
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D.
50 N
Solution
At rest, the tension in the rope equals the weight of the object: T = mg = 10 kg * 10 m/s² = 100 N.
Correct Answer: C — 100 N
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Q. A 10 kg object is lifted to a height of 10 m. How much work is done against gravity?
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A.
0 J
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B.
100 J
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C.
200 J
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D.
1000 J
Solution
Work done against gravity is equal to the change in potential energy, W = mgh = 10 * 9.8 * 10 = 980 J.
Correct Answer: D — 1000 J
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Q. A 10 kg object is lifted to a height of 2 m. What is the work done against gravity?
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A.
20 J
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B.
40 J
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C.
60 J
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D.
80 J
Solution
Work done = mass × g × height = 10 kg × 9.8 m/s² × 2 m = 196 J.
Correct Answer: B — 40 J
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Q. A 10 kg object is lifted to a height of 5 m. How much work is done against gravity?
-
A.
50 J
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B.
100 J
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C.
150 J
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D.
200 J
Solution
Work done = mgh = 10 * 9.8 * 5 = 490 J.
Correct Answer: B — 100 J
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Q. A 10 kg object is lifted to a height of 5 m. What is the potential energy gained by the object?
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A.
50 J
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B.
100 J
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C.
150 J
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D.
200 J
Solution
Potential energy (PE) = mgh = 10 kg * 9.8 m/s² * 5 m = 490 J.
Correct Answer: B — 100 J
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Q. A 10 kg object is lifted to a height of 5 m. What is the work done against gravity?
-
A.
50 J
-
B.
100 J
-
C.
150 J
-
D.
200 J
Solution
Work done against gravity = mgh = 10 * 9.8 * 5 = 490 J.
Correct Answer: B — 100 J
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Q. A 10 kg object is moving in a circular path of radius 5 m with a speed of 10 m/s. What is the centripetal force acting on the object?
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A.
20 N
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B.
10 N
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C.
5 N
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D.
50 N
Solution
Centripetal force F = mv²/r = 10 kg * (10 m/s)² / 5 m = 200 N.
Correct Answer: A — 20 N
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Q. A 10 kg object is moving in a circular path of radius 5 m with a speed of 4 m/s. What is the centripetal force acting on the object?
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A.
8 N
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B.
16 N
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C.
32 N
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D.
40 N
Solution
Centripetal force F = mv²/r = 10 kg * (4 m/s)² / 5 m = 32 N.
Correct Answer: B — 16 N
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Q. A 10 kg object is moving with a speed of 3 m/s. If it comes to a stop, how much work is done by the friction force?
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A.
45 J
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B.
90 J
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C.
135 J
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D.
180 J
Solution
Work done = Change in Kinetic Energy = 0 - (0.5 × 10 kg × (3 m/s)²) = -45 J.
Correct Answer: B — 90 J
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Q. A 10 kg object is moving with a speed of 3 m/s. What is its kinetic energy?
-
A.
45 J
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B.
30 J
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C.
60 J
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D.
90 J
Solution
Kinetic Energy = 0.5 × mass × velocity² = 0.5 × 10 kg × (3 m/s)² = 45 J.
Correct Answer: A — 45 J
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Q. A 10 kg object is moving with a speed of 5 m/s. What is its total mechanical energy?
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A.
125 J
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B.
250 J
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C.
500 J
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D.
1000 J
Solution
Total mechanical energy = KE + PE. KE = 0.5 * 10 * (5)² = 125 J. Assuming PE = 0, total energy = 125 J.
Correct Answer: B — 250 J
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Q. A 10 kg object is moving with a velocity of 2 m/s. If it comes to rest, what is the change in momentum?
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A.
20 kg·m/s
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B.
10 kg·m/s
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C.
5 kg·m/s
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D.
0 kg·m/s
Solution
Initial momentum = mv = 10 kg * 2 m/s = 20 kg·m/s. Final momentum = 0. Change in momentum = 20 kg·m/s - 0 = 20 kg·m/s.
Correct Answer: A — 20 kg·m/s
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Q. A 10 kg object is moving with a velocity of 3 m/s. What is its kinetic energy?
-
A.
15 J
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B.
30 J
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C.
45 J
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D.
60 J
Solution
Kinetic energy = 0.5 × m × v² = 0.5 × 10 kg × (3 m/s)² = 45 J.
Correct Answer: C — 45 J
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Q. A 10 kg object is moving with a velocity of 3 m/s. What is its momentum?
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A.
10 kg·m/s
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B.
30 kg·m/s
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C.
3 kg·m/s
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D.
0.3 kg·m/s
Solution
Momentum p = mv = 10 kg * 3 m/s = 30 kg·m/s.
Correct Answer: B — 30 kg·m/s
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Q. A 10 kg object is moving with a velocity of 3 m/s. What is the total mechanical energy if it is at a height of 5 m?
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A.
150 J
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B.
180 J
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C.
300 J
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D.
450 J
Solution
Total Mechanical Energy = Kinetic Energy + Potential Energy = 0.5 × 10 kg × (3 m/s)² + 10 kg × 9.8 m/s² × 5 m = 45 J + 490 J = 535 J.
Correct Answer: C — 300 J
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Q. A 10 kg object is moving with a velocity of 4 m/s. What is its momentum?
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A.
40 kg m/s
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B.
20 kg m/s
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C.
10 kg m/s
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D.
30 kg m/s
Solution
Momentum (p) = m * v = 10 kg * 4 m/s = 40 kg m/s
Correct Answer: A — 40 kg m/s
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Q. A 10 kg object is moving with a velocity of 5 m/s. What is its momentum?
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A.
10 kg·m/s
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B.
25 kg·m/s
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C.
50 kg·m/s
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D.
75 kg·m/s
Solution
Momentum p = mv = 10 kg * 5 m/s = 50 kg·m/s.
Correct Answer: C — 50 kg·m/s
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Q. A 10 kg object is pushed with a force of 30 N. If the frictional force is 10 N, what is the net force?
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A.
10 N
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B.
20 N
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C.
30 N
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D.
40 N
Solution
Net force = applied force - friction = 30 N - 10 N = 20 N.
Correct Answer: B — 20 N
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Q. A 10 kg object is thrown upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 9.8 m/s²)
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A.
11.5 m
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B.
22.5 m
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C.
15.3 m
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D.
10.0 m
Solution
Using conservation of energy, KE at the bottom = PE at the top. 0.5mv² = mgh. Solving gives h = v²/(2g) = (15)²/(2*9.8) = 11.5 m.
Correct Answer: A — 11.5 m
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Q. A 10 kg object is thrown vertically upwards with a speed of 15 m/s. What is the maximum height it reaches? (g = 10 m/s²)
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A.
11.25 m
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B.
22.5 m
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C.
15 m
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D.
7.5 m
Solution
Using energy conservation: KE_initial = PE_max; 1/2 * m * v^2 = m * g * h; h = v^2 / (2g) = (15^2) / (2 * 10) = 11.25 m
Correct Answer: A — 11.25 m
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Q. A 10 Ω resistor and a 20 Ω resistor are connected in series. What is the total resistance?
-
A.
10 Ω
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B.
20 Ω
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C.
30 Ω
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D.
5 Ω
Solution
In series, the total resistance R = R1 + R2 = 10 Ω + 20 Ω = 30 Ω.
Correct Answer: C — 30 Ω
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Q. A 10-ohm resistor and a 20-ohm resistor are connected in series. What is the total resistance?
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A.
10 ohms
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B.
20 ohms
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C.
30 ohms
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D.
5 ohms
Solution
In series, the total resistance R = R1 + R2 = 10 + 20 = 30 ohms.
Correct Answer: C — 30 ohms
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Q. A 10-ohm resistor has a voltage of 20 volts across it. What is the current flowing through the resistor?
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A.
1 A
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B.
2 A
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C.
3 A
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D.
4 A
Solution
Using Ohm's Law, I = V / R = 20 V / 10 Ω = 2 A.
Correct Answer: B — 2 A
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Q. A 10-ohm resistor has a voltage of 50 volts across it. What is the current flowing through the resistor?
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A.
5 A
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B.
10 A
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C.
15 A
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D.
20 A
Solution
Using Ohm's Law, I = V / R = 50 V / 10 Ω = 5 A.
Correct Answer: B — 10 A
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Q. A 10-ohm resistor is connected to a 20-volt battery. What is the power dissipated by the resistor?
-
A.
40 W
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B.
20 W
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C.
10 W
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D.
2 W
Solution
Power (P) can be calculated using P = V^2 / R = 20^2 / 10 = 400 / 10 = 40 W.
Correct Answer: A — 40 W
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Q. A 1000 kg car accelerates from rest to a speed of 20 m/s in 10 seconds. What is the average power exerted by the engine?
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A.
2000 W
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B.
4000 W
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C.
5000 W
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D.
6000 W
Solution
First, calculate the work done: W = (1/2)mv^2 = (1/2)(1000 kg)(20 m/s)^2 = 200000 J. Then, power is P = W/t = 200000 J / 10 s = 20000 W.
Correct Answer: C — 5000 W
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Q. A 1000 W heater operates for 1 hour. How much energy does it consume?
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A.
3600 J
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B.
1000 J
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C.
3600000 J
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D.
100000 J
Solution
Energy consumed is E = P * t. Here, P = 1000 W and t = 1 hour = 3600 seconds. Thus, E = 1000 W * 3600 s = 3600000 J.
Correct Answer: C — 3600000 J
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Q. A 1000 W heater operates for 2 hours. How much energy does it consume?
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A.
7200000 J
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B.
2000000 J
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C.
3600000 J
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D.
1000000 J
Solution
Energy consumed can be calculated using E = P * t. Here, P = 1000 W and t = 2 hours = 7200 seconds. Thus, E = 1000 W * 7200 s = 7200000 J.
Correct Answer: C — 3600000 J
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