A 10 kg object is moving in a circular path of radius 5 m with a speed of 10 m/s. What is the centripetal force acting on the object?

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Q: A 10 kg object is moving in a circular path of radius 5 m with a speed of 10 m/s. What is the centripetal force acting on the object?

Solution: Centripetal force F = mv²/r = 10 kg * (10 m/s)² / 5 m = 200 N.

Steps: 9

Step 1: Identify the mass of the object. The mass (m) is given as 10 kg.
Step 2: Identify the speed of the object. The speed (v) is given as 10 m/s.
Step 3: Identify the radius of the circular path. The radius (r) is given as 5 m.
Step 4: Use the formula for centripetal force, which is F = mv²/r.
Step 5: Substitute the values into the formula: F = 10 kg * (10 m/s)² / 5 m.
Step 6: Calculate (10 m/s)², which equals 100 m²/s².
Step 7: Multiply 10 kg by 100 m²/s² to get 1000 kg*m²/s².
Step 8: Divide 1000 kg*m²/s² by 5 m to find the centripetal force.
Step 9: The result is 200 N, which is the centripetal force acting on the object.