Laws of Motion
Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to maintain the circular motion at the same speed?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
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Solution
Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for constant speed.
Correct Answer: C — It halves
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Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to keep the stone moving in a circle at the same speed?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
Show solution
Solution
Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for the same speed.
Correct Answer: C — It halves
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Q. A stone is tied to a string and whirled in a horizontal circle. If the radius of the circle is doubled, what happens to the centripetal force required to maintain the stone's circular motion at the same speed?
A.
It doubles
B.
It remains the same
C.
It halves
D.
It quadruples
Show solution
Solution
Centripetal force (F_c) = mv²/r. If r is doubled, F_c is halved for constant speed.
Correct Answer: C — It halves
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Q. A stone is tied to a string and whirled in a vertical circle of radius 1 m. What is the minimum speed at the top of the circle to keep the stone in circular motion?
A.
1 m/s
B.
2 m/s
C.
3 m/s
D.
4 m/s
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Solution
At the top, centripetal force = weight. mv²/r = mg. v² = rg. v = √(1*9.8) ≈ 3.13 m/s.
Correct Answer: B — 2 m/s
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Q. A train of mass 1000 kg is moving with a velocity of 36 km/h. What is its kinetic energy?
A.
500 J
B.
1000 J
C.
1800 J
D.
2000 J
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Solution
First convert velocity to m/s: 36 km/h = 10 m/s. K.E. = (1/2)mv² = (1/2)(1000 kg)(10 m/s)² = 50000 J.
Correct Answer: C — 1800 J
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Q. According to Newton's third law, if object A exerts a force on object B, what does object B do?
A.
Exerts a greater force on A
B.
Exerts an equal and opposite force on A
C.
Exerts no force
D.
Exerts a lesser force on A
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Solution
Newton's third law states that for every action, there is an equal and opposite reaction.
Correct Answer: B — Exerts an equal and opposite force on A
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Q. An object is in equilibrium. If two forces of 10 N and 15 N act on it in opposite directions, what is the net force?
A.
5 N
B.
10 N
C.
15 N
D.
0 N
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Solution
In equilibrium, the net force is zero. The forces cancel each other out: 15 N - 10 N = 5 N.
Correct Answer: A — 5 N
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Q. An object is in equilibrium. What can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is maximum
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Solution
For an object in equilibrium, the net force acting on it must be zero.
Correct Answer: A — It is zero
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Q. An object is moving in a circular path with a radius of 10 m and a speed of 5 m/s. What is the net force acting on the object if its mass is 2 kg?
A.
1 N
B.
2 N
C.
5 N
D.
10 N
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Solution
Centripetal force (F_c) = mv²/r = 2 kg * (5 m/s)² / (10 m) = 5 N.
Correct Answer: D — 10 N
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Q. An object is moving in a circular path with a radius of 3 m and an angular speed of 2 rad/s. What is the linear speed of the object?
A.
3 m/s
B.
6 m/s
C.
9 m/s
D.
12 m/s
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Solution
Linear speed (v) = rω = 3 m * 2 rad/s = 6 m/s.
Correct Answer: B — 6 m/s
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Q. If a 10 kg object is in free fall, what is the force acting on it due to gravity?
A.
10 N
B.
20 N
C.
30 N
D.
40 N
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Solution
The force due to gravity is F = mg = 10 kg * 9.8 m/s² = 98 N, which rounds to 100 N.
Correct Answer: B — 20 N
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Q. If a 10 kg object is pulled with a force of 30 N, what is its acceleration?
A.
1 m/s²
B.
2 m/s²
C.
3 m/s²
D.
4 m/s²
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Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer: C — 3 m/s²
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Q. If a 10 kg object is pulled with a force of 50 N, what is its acceleration?
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
20 m/s²
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Solution
Using F = ma, a = F/m = 50 N / 10 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. If a 10 kg object is subjected to a net force of 30 N, what is the object's acceleration?
A.
3 m/s²
B.
2 m/s²
C.
1.5 m/s²
D.
4 m/s²
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Solution
Using F = ma, a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer: A — 3 m/s²
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Q. If a 10 kg object is subjected to a net force of 30 N, what will be its acceleration?
A.
3 m/s²
B.
0.3 m/s²
C.
30 m/s²
D.
300 m/s²
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Solution
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Correct Answer: A — 3 m/s²
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Q. If a 10 kg object is subjected to a net force of 50 N, what is its acceleration?
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
15 m/s²
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Solution
Using F = ma, acceleration a = F/m = 50 N / 10 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. If a 10 kg object is subjected to a net force of 50 N, what will be its acceleration?
A.
2 m/s²
B.
5 m/s²
C.
10 m/s²
D.
20 m/s²
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Solution
Using F = ma, acceleration a = F/m = 50 N / 10 kg = 5 m/s².
Correct Answer: B — 5 m/s²
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Q. If a 12 kg object is moving with a constant velocity, what can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is increasing
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Solution
An object moving with constant velocity has a net force of zero according to Newton's first law.
Correct Answer: A — It is zero
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Q. If a 12 kg object is pushed with a force of 48 N, what is the acceleration of the object?
A.
2 m/s²
B.
4 m/s²
C.
6 m/s²
D.
8 m/s²
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Solution
Using F = ma, acceleration a = F/m = 48 N / 12 kg = 4 m/s².
Correct Answer: B — 4 m/s²
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Q. If a 2 kg object is acted upon by a net force of 6 N, what is the object's acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we find a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. If a 2 kg object is moving with a velocity of 3 m/s and a force of 6 N is applied in the opposite direction, what will be its final velocity after 2 seconds?
A.
0 m/s
B.
1 m/s
C.
2 m/s
D.
3 m/s
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Solution
Net force = -6 N, acceleration = F/m = -6 N / 2 kg = -3 m/s². Final velocity = initial velocity + at = 3 m/s + (-3 m/s² * 2 s) = 0 m/s.
Correct Answer: B — 1 m/s
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Q. If a 2 kg object is pulled with a force of 10 N and experiences a frictional force of 4 N, what is its acceleration?
A.
3 m/s²
B.
5 m/s²
C.
2 m/s²
D.
1 m/s²
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Solution
Net force = applied force - friction = 10 N - 4 N = 6 N. Acceleration a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer: A — 3 m/s²
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Q. If a 2 kg object is subjected to a net force of 6 N, what is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we have a = F/m = 6 N / 2 kg = 3 m/s².
Correct Answer: B — 3 m/s²
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Q. If a 3 kg object is in free fall, what is the force acting on it due to gravity?
A.
3 N
B.
9 N
C.
30 N
D.
None of the above
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Solution
Force due to gravity F = mg = 3 kg * 9.8 m/s² = 29.4 N, approximately 9 N for simplification.
Correct Answer: B — 9 N
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Q. If a 4 kg object is acted upon by a net force of 16 N, what is its acceleration?
A.
2 m/s²
B.
3 m/s²
C.
4 m/s²
D.
5 m/s²
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Solution
Using F = ma, we have a = F/m = 16 N / 4 kg = 4 m/s².
Correct Answer: C — 4 m/s²
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Q. If a 4 kg object is at rest and a net force of 8 N is applied, what will be its velocity after 2 seconds?
A.
4 m/s
B.
2 m/s
C.
1 m/s
D.
0 m/s
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Solution
Using F = ma, a = F/m = 8 N / 4 kg = 2 m/s². Velocity after 2 seconds = a * t = 2 m/s² * 2 s = 4 m/s.
Correct Answer: B — 2 m/s
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Q. If a 4 kg object is moving with a constant velocity, what can be said about the net force acting on it?
A.
It is zero
B.
It is equal to its weight
C.
It is equal to the applied force
D.
It is maximum
Show solution
Solution
According to Newton's first law, if an object is moving with constant velocity, the net force acting on it is zero.
Correct Answer: A — It is zero
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Q. If a 5 kg object is in free fall, what is the force acting on it due to gravity?
A.
5 N
B.
10 N
C.
50 N
D.
15 N
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Solution
The force due to gravity F = mg = 5 kg * 10 m/s² = 50 N.
Correct Answer: C — 50 N
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Q. If a 5 kg object is subjected to a force of 20 N, what is its acceleration?
A.
2 m/s²
B.
4 m/s²
C.
5 m/s²
D.
10 m/s²
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Solution
Using F = ma, acceleration a = F/m = 20 N / 5 kg = 4 m/s².
Correct Answer: B — 4 m/s²
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Q. If a 6 kg object is subjected to a net force of 24 N, what is its acceleration?
A.
4 m/s²
B.
6 m/s²
C.
8 m/s²
D.
10 m/s²
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Solution
Using F = ma, acceleration a = F/m = 24 N / 6 kg = 4 m/s².
Correct Answer: A — 4 m/s²
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