General Knowledge
Q. A meal contains 800 calories, with 40% from carbohydrates, 30% from proteins, and 30% from fats. How many calories are from carbohydrates?
A.
240 calories
B.
320 calories
C.
400 calories
D.
480 calories
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Solution
40% of 800 calories = 0.40 * 800 = 320 calories.
Correct Answer: B — 320 calories
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Q. A military base has a rectangular area of 200 m by 150 m. What is the area of the base? (2019)
A.
30000 m²
B.
25000 m²
C.
20000 m²
D.
15000 m²
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Solution
Area = Length × Width = 200 m × 150 m = 30000 m²
Correct Answer: B — 25000 m²
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Q. A national event is expected to attract 1,200 visitors. If 15% of them are expected to be children, how many children are expected?
A.
180
B.
150
C.
200
D.
120
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Solution
Number of children expected = 1,200 * 0.15 = 180.
Correct Answer: A — 180
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Q. A national festival lasts for 5 days. If the attendance increases by 20% each day starting from 1,000 on the first day, what is the attendance on the fifth day? (2073)
A.
2,488
B.
2,000
C.
2,400
D.
2,500
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Solution
Attendance on the fifth day = 1000 * (1 + 0.20)^4 = 1000 * 2.0736 = 2073.6 ≈ 2074.
Correct Answer: A — 2,488
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Q. A pendulum swings with a period of 2 seconds. What is the length of the pendulum? (Take g = 10 m/s²)
A.
1 m
B.
2 m
C.
0.5 m
D.
0.25 m
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Solution
Using the formula T = 2π√(l/g), we have l = (T² * g)/(4π²) = (2² * 10)/(4π²) = 1 m.
Correct Answer: B — 2 m
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Q. A person is on a diet that consists of 50% carbohydrates, 30% fats, and 20% proteins. If they consume 1800 calories, how many calories are from carbohydrates?
A.
600 calories
B.
700 calories
C.
800 calories
D.
900 calories
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Solution
50% of 1800 calories = 0.50 * 1800 = 900 calories from carbohydrates.
Correct Answer: C — 800 calories
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Q. A person needs 2000 calories a day and wants to get 15% of their calories from fats. How many grams of fat should they consume (1 gram of fat = 9 calories)? (2000)
A.
33 grams
B.
40 grams
C.
50 grams
D.
60 grams
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Solution
15% of 2000 calories = 0.15 * 2000 = 300 calories from fats. 300 calories / 9 calories per gram = 33.33 grams, rounded to 33 grams.
Correct Answer: B — 40 grams
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Q. A person walks 3 km north and then 4 km east. What is the straight-line distance from the starting point? (2021)
A.
5 km
B.
6 km
C.
7 km
D.
8 km
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Solution
Using Pythagoras theorem, distance = √(3² + 4²) = √(9 + 16) = √25 = 5 km.
Correct Answer: A — 5 km
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Q. A person walks 3 km towards the north and then 4 km towards the east. What is the straight-line distance from the starting point? (2020)
A.
5 km
B.
6 km
C.
7 km
D.
8 km
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Solution
Using Pythagoras theorem, distance = √(3² + 4²) = √(9 + 16) = √25 = 5 km.
Correct Answer: A — 5 km
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Q. A player has a batting average of 50 runs. If he has played 20 matches, how many runs has he scored in total? (2019)
A.
800
B.
1000
C.
900
D.
700
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Solution
Total runs scored = Batting average * Number of matches = 50 * 20 = 1000 runs.
Correct Answer: A — 800
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Q. A player runs 100 meters in 12 seconds. What is his average speed in m/s? (2019)
A.
8.33
B.
9.00
C.
7.50
D.
8.00
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Solution
Average speed = Distance / Time = 100 meters / 12 seconds = 8.33 m/s.
Correct Answer: A — 8.33
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Q. A player scores 15 points in a game. If he plays 10 games, what is the total number of points scored? (2023)
A.
150
B.
120
C.
130
D.
140
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Solution
Total points scored = 15 points/game * 10 games = 150 points.
Correct Answer: A — 150
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Q. A projectile is launched at an angle of 30° with the horizontal with an initial velocity of 40 m/s. What is the horizontal range of the projectile? (Take g = 10 m/s²)
A.
160 m
B.
200 m
C.
80 m
D.
120 m
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Solution
Range R = (u² * sin(2θ))/g = (40² * sin(60°))/10 = (1600 * √3/2)/10 = 80√3 m ≈ 138.56 m.
Correct Answer: B — 200 m
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Q. A radar system can detect objects up to 100 km away. If an object is detected at 75 km, how far is it from the radar? (2022)
A.
25 km
B.
50 km
C.
75 km
D.
100 km
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Solution
Distance from Radar = Maximum Range - Detected Distance = 100 km - 75 km = 25 km
Correct Answer: A — 25 km
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Q. A ray of light strikes a plane mirror at an angle of 30 degrees to the normal. What is the angle of reflection? (2022)
A.
30 degrees
B.
45 degrees
C.
60 degrees
D.
90 degrees
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Solution
According to the law of reflection, the angle of reflection is equal to the angle of incidence. Therefore, the angle of reflection is 30 degrees.
Correct Answer: A — 30 degrees
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Q. A rectangle has a length of 10 cm and a width of 5 cm. What is its area? (2022)
A.
50 cm²
B.
60 cm²
C.
40 cm²
D.
30 cm²
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Solution
Area = Length * Width = 10 cm * 5 cm = 50 cm².
Correct Answer: A — 50 cm²
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Q. A rectangle has a length of 10 cm and a width of 5 cm. What is the area of the rectangle? (2022)
A.
50 cm²
B.
25 cm²
C.
15 cm²
D.
30 cm²
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Solution
Area = Length × Width = 10 cm × 5 cm = 50 cm².
Correct Answer: A — 50 cm²
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Q. A river basin has an area of 500 km². If the average rainfall is 800 mm per year, what is the total volume of water received by the basin in a year? (2019)
A.
400,000,000 m³
B.
500,000,000 m³
C.
600,000,000 m³
D.
700,000,000 m³
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Solution
Volume = area × rainfall = 500 km² × 800 mm = 500,000,000 m³.
Correct Answer: A — 400,000,000 m³
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Q. A river carries 1500 m³ of water per second. If the river's width is 25 m, what is the average depth of the river?
A.
6 m
B.
5 m
C.
4 m
D.
3 m
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Solution
Discharge = Width × Depth × Velocity. Assuming velocity = 1 m/s, Depth = Discharge / (Width × Velocity) = 1500 m³/s / (25 m × 1 m/s) = 60 m.
Correct Answer: B — 5 m
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Q. A river flows at a speed of 3 m/s. How far will it travel in 2 hours? (2020)
A.
21600 m
B.
7200 m
C.
10800 m
D.
3600 m
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Solution
Distance = speed × time = 3 m/s × 7200 s = 21600 m.
Correct Answer: A — 21600 m
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Q. A river flows through a region with a soil erosion rate of 5 tons per hectare per year. If the area of the watershed is 100 hectares, how much soil is eroded in a year?
A.
500 tons
B.
1000 tons
C.
200 tons
D.
300 tons
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Solution
Soil eroded = Erosion rate × Area = 5 tons/hectare/year × 100 hectares = 500 tons/year.
Correct Answer: B — 1000 tons
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Q. A river has a cross-sectional area of 150 m² and flows at a velocity of 4 m/s. What is the discharge of the river? (2021)
A.
600 m³/s
B.
400 m³/s
C.
300 m³/s
D.
200 m³/s
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Solution
Discharge = area × velocity = 150 m² × 4 m/s = 600 m³/s.
Correct Answer: A — 600 m³/s
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Q. A river has a length of 100 km and a drainage area of 500 km². What is the average discharge per square kilometer?
A.
0.2 m³/s
B.
0.5 m³/s
C.
1 m³/s
D.
1.5 m³/s
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Solution
Average discharge = Total discharge / Drainage area. Assuming total discharge = 250 m³/s, Average discharge = 250 m³/s / 500 km² = 0.5 m³/s.
Correct Answer: B — 0.5 m³/s
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Q. A river's velocity is measured at 2 m/s. If the river's width is 10 m and depth is 3 m, what is the discharge?
A.
60 m³/s
B.
30 m³/s
C.
20 m³/s
D.
10 m³/s
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Solution
Discharge = Velocity × Area. Area = Width × Depth = 10 m × 3 m = 30 m². Discharge = 2 m/s × 30 m² = 60 m³/s.
Correct Answer: B — 30 m³/s
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Q. A river's width is 15 m and its average depth is 2 m. What is the cross-sectional area of the river?
A.
30 m²
B.
15 m²
C.
45 m²
D.
60 m²
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Solution
Cross-sectional area = Width × Depth = 15 m × 2 m = 30 m².
Correct Answer: D — 60 m²
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Q. A runner completes a 400 m lap in 50 seconds. What is the average speed of the runner in m/s? (2019)
A.
6 m/s
B.
7 m/s
C.
8 m/s
D.
9 m/s
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Solution
Average speed = Total distance / Total time = 400 m / 50 s = 8 m/s.
Correct Answer: A — 6 m/s
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Q. A school awards a trophy to the top 10% of students. If there are 200 students, how many students receive the trophy?
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Solution
Number of students receiving trophy = 10% of 200 = 0.1 * 200 = 20.
Correct Answer: C — 20
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Q. A shopkeeper sells a shirt for Rs. 800 after giving a discount of 20%. What was the marked price of the shirt? (2020)
A.
Rs. 1000
B.
Rs. 900
C.
Rs. 800
D.
Rs. 750
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Solution
Let marked price = x. Then, 0.8x = 800 => x = 800/0.8 = 1000.
Correct Answer: A — Rs. 1000
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Q. A shopkeeper sells an article for Rs. 800, making a profit of 20%. What was the cost price of the article? (2020)
A.
Rs. 600
B.
Rs. 640
C.
Rs. 500
D.
Rs. 700
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Solution
Let CP = x. Then, 800 = x + 0.20x = 1.20x. Therefore, x = 800 / 1.20 = 666.67.
Correct Answer: A — Rs. 600
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Q. A snack contains 150 calories, with 10% from protein, 50% from carbohydrates, and 40% from fats. How many calories are from fats?
A.
40 calories
B.
50 calories
C.
60 calories
D.
70 calories
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Solution
40% of 150 calories = 0.40 * 150 = 60 calories from fats.
Correct Answer: C — 60 calories
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