Sulfuric acid is primarily used as battery acid in lead-acid batteries.

Sodium has an atomic number of 11, and its outermost electron is in the 3rd shell, so n=3.

Sodium has the electronic configuration of 1s² 2s² 2p⁶ 3s¹, so the principal quantum number for the outermost electrons is 3.

Number of kings = 4. Probability = 4/52 = 1/13.

Number of queens = 4. Probability = 4/52 = 1/13.

There are 2 outcomes: heads or tails. Probability of heads = 1/2.

Possible combinations for sum of 7 = (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) = 6. Total outcomes = 36. Probability = 6/36 = 1/6.

The process of a solid turning directly into a gas is called sublimation.

The process of forming a polymer from monomers is called polymerization.

1-bromopropane reacts with sodium hydroxide in ethanol to form 1-propanol through a nucleophilic substitution reaction.

9 × 6 = 54.

9 × 7 = 63.

The products of electrolysis of water are hydrogen and oxygen.

The complete combustion of propane produces carbon dioxide (CO2) and water (H2O).

(1 + i)(1 - i) = 1^2 - i^2 = 1 - (-1) = 2.

(2 + 3i)(4 - i) = 8 - 2i + 12i - 3i^2 = 8 + 10i + 3 = 11 + 10i.

2-Propanol oxidizes to form Acetone, which is a ketone.

The oxidation of a primary alcohol first produces an aldehyde, which can further oxidize to a carboxylic acid.

The oxidation of a primary alcohol results in the formation of an aldehyde.

Ethanol oxidizes to acetic acid when reacted with an oxidizing agent.

Propan-2-ol oxidizes to form Acetone (CH3COCH3).

The reaction of 1-bromobutane with sodium hydroxide in ethanol leads to the formation of butanol through nucleophilic substitution.

1-bromopropane reacts with sodium hydroxide in ethanol to form 1-Propanol via nucleophilic substitution.

The reaction produces Ethylamine as ammonia acts as a nucleophile and replaces the bromine atom.

The reaction between an amine and an acid produces a salt, as the amine acts as a base and accepts a proton from the acid.

The reaction produces Diphenylmethanol when benzaldehyde reacts with phenylmagnesium bromide.

In acidic medium, Cr2O7^2- is reduced to Cr^3+.

The product of the roots is given by c/a = 9/3 = 3.

The product of the roots is c/a = 6/1 = 6.

The product of the roots is given by c/a = 6/1 = 6.