Circuits & Kirchhoff Laws
Q. What is the effect on the total resistance in a circuit when more resistors are added in series?
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A.
Increases
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B.
Decreases
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C.
Remains the same
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D.
Becomes zero
Solution
Adding more resistors in series increases the total resistance, as total resistance is the sum of individual resistances.
Correct Answer: A — Increases
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Q. What is the effect on the total resistance when more resistors are added in parallel to a circuit?
-
A.
Increases
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B.
Decreases
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C.
Remains the same
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D.
Doubles
Solution
Adding more resistors in parallel decreases the total resistance of the circuit.
Correct Answer: B — Decreases
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Q. What is the equivalent resistance of a circuit with a 10 ohm and a 5 ohm resistor in series?
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A.
15 ohms
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B.
5 ohms
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C.
10 ohms
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D.
20 ohms
Solution
For resistors in series, R_eq = R1 + R2 = 10 ohms + 5 ohms = 15 ohms.
Correct Answer: A — 15 ohms
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Q. What is the equivalent resistance of a circuit with two 10Ω resistors in series and one 5Ω resistor in parallel with them?
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A.
5Ω
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B.
10Ω
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C.
15Ω
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D.
20Ω
Solution
R_series = 10Ω + 10Ω = 20Ω. R_parallel = 1/(1/20 + 1/5) = 4Ω. Therefore, R_eq = 4Ω.
Correct Answer: C — 15Ω
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Q. What is the equivalent resistance of a circuit with two resistors R1 = 10Ω and R2 = 10Ω in parallel?
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A.
5Ω
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B.
10Ω
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C.
20Ω
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D.
15Ω
Solution
The equivalent resistance in parallel is given by 1/R_total = 1/R1 + 1/R2 = 1/10 + 1/10 = 1/5. Therefore, R_total = 5Ω.
Correct Answer: A — 5Ω
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Q. What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 5Ω connected in parallel?
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A.
1Ω
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B.
2Ω
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C.
0.83Ω
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D.
10Ω
Solution
1/Req = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/5 = 0.8333, thus Req = 1.2Ω.
Correct Answer: C — 0.83Ω
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Q. What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in parallel?
Solution
1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6 = 1. Therefore, R_eq = 1Ω.
Correct Answer: A — 1Ω
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Q. What is the equivalent resistance of three resistors of values 2Ω, 3Ω, and 5Ω connected in parallel?
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A.
1Ω
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B.
2Ω
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C.
0.83Ω
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D.
10Ω
Solution
1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/5 = 0.8333, thus R_eq = 1.2Ω.
Correct Answer: C — 0.83Ω
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Q. What is the equivalent resistance of three resistors of values 2Ω, 3Ω, and 6Ω connected in parallel?
Solution
1/Req = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6 = 1. Therefore, Req = 1Ω.
Correct Answer: B — 2Ω
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Q. What is the equivalent resistance of two resistors of 10 ohms and 20 ohms connected in series?
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A.
30 ohms
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B.
20 ohms
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C.
10 ohms
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D.
5 ohms
Solution
In series, the equivalent resistance R_eq = R1 + R2 = 10 ohms + 20 ohms = 30 ohms.
Correct Answer: A — 30 ohms
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Q. What is the equivalent resistance of two resistors of 4Ω and 12Ω connected in parallel?
Solution
Using the formula for parallel resistors, 1/R_eq = 1/R1 + 1/R2 = 1/4 + 1/12 = 1/3. Therefore, R_eq = 3Ω.
Correct Answer: C — 6Ω
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Q. What is the equivalent resistance of two resistors of 5 ohms and 10 ohms connected in parallel?
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A.
3.33 ohms
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B.
15 ohms
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C.
5 ohms
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D.
7.5 ohms
Solution
Using the formula for resistors in parallel, 1/R_eq = 1/R1 + 1/R2, we find R_eq = 1 / (1/5 + 1/10) = 3.33 ohms.
Correct Answer: A — 3.33 ohms
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Q. What is the equivalent resistance of two resistors of 5Ω and 10Ω connected in parallel?
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A.
3.33Ω
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B.
5Ω
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C.
7.5Ω
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D.
15Ω
Solution
1/Req = 1/R1 + 1/R2 = 1/5 + 1/10 = 2/10 + 1/10 = 3/10. Therefore, Req = 10/3 = 3.33Ω.
Correct Answer: A — 3.33Ω
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Q. What is the potential difference across a 10Ω resistor if a current of 2A flows through it?
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A.
5V
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B.
10V
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C.
20V
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D.
15V
Solution
Using Ohm's Law, V = I * R = 2A * 10Ω = 20V.
Correct Answer: C — 20V
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Q. What is the potential difference across a 10Ω resistor if a current of 4A flows through it?
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A.
20V
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B.
40V
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C.
10V
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D.
30V
Solution
Using Ohm's Law, V = I * R = 4A * 10Ω = 40V.
Correct Answer: A — 20V
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Q. What is the power dissipated in a 10Ω resistor carrying a current of 2A?
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A.
20W
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B.
30W
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C.
40W
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D.
50W
Solution
Power P = I^2 * R = (2A)^2 * 10Ω = 4 * 10 = 40W.
Correct Answer: A — 20W
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Q. What is the power dissipated in a 4 ohm resistor carrying a current of 3 A?
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A.
12 W
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B.
9 W
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C.
6 W
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D.
3 W
Solution
Using the power formula P = I^2 * R, we have P = (3 A)^2 * 4 ohms = 9 * 4 = 36 W.
Correct Answer: A — 12 W
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Q. What is the power dissipated in a resistor of 10 ohms carrying a current of 2 A?
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A.
20 W
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B.
10 W
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C.
5 W
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D.
40 W
Solution
Using the power formula P = I^2 * R, we have P = (2 A)^2 * 10 ohms = 4 * 10 = 40 W.
Correct Answer: A — 20 W
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Q. What is the power dissipated in a resistor of 5Ω carrying a current of 2A?
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A.
5W
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B.
10W
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C.
20W
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D.
40W
Solution
Power is given by P = I^2 * R = (2A)^2 * 5Ω = 4A^2 * 5Ω = 20W.
Correct Answer: B — 10W
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Q. What is the power dissipated in a resistor of 5Ω carrying a current of 3A?
Solution
Power P = I^2 * R = (3A)^2 * 5Ω = 9A^2 * 5Ω = 45W.
Correct Answer: A — 15W
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Q. What is the total current flowing through a circuit if the total voltage is 12 V and the total resistance is 4 ohms?
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A.
3 A
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B.
4 A
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C.
12 A
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D.
48 A
Solution
Using Ohm's Law, I = V / R. Here, I = 12 V / 4 ohms = 3 A.
Correct Answer: A — 3 A
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Q. What is the total current flowing through a circuit if the total voltage is 12V and the total resistance is 4Ω?
Solution
Using Ohm's Law (I = V/R), the current is I = 12V / 4Ω = 3A.
Correct Answer: B — 3A
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Q. What is the total current flowing through a circuit if the total voltage is 24V and the total resistance is 6Ω?
Solution
Using Ohm's Law, I = V/R = 24V / 6Ω = 4A.
Correct Answer: B — 4A
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Q. What is the total current flowing through a circuit with a 10V battery and two 5Ω resistors in parallel?
Solution
Equivalent resistance R_eq = 1/(1/5 + 1/5) = 2.5Ω. Total current I = V/R_eq = 10V/2.5Ω = 4A.
Correct Answer: B — 2A
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Q. What is the total current flowing through a circuit with a 10V battery and two 5Ω resistors in series?
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A.
0.5A
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B.
1A
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C.
2A
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D.
5A
Solution
Total resistance R = R1 + R2 = 5Ω + 5Ω = 10Ω. Using Ohm's law, I = V/R = 10V/10Ω = 1A.
Correct Answer: B — 1A
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Q. What is the total current flowing through a junction where 5A enters and 3A and 2A leave?
Solution
According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving. Here, 5A = 3A + 2A.
Correct Answer: A — 0A
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Q. What is the total current in a circuit with a 12V battery and a total resistance of 3 ohms?
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A.
4 A
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B.
2 A
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C.
3 A
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D.
1 A
Solution
Using Ohm's law, I = V/R, we have I = 12V / 3 ohms = 4 A.
Correct Answer: A — 4 A
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Q. What is the total current in a circuit with a 12V battery and three resistors (R1 = 4Ω, R2 = 4Ω, R3 = 4Ω) connected in parallel?
Solution
Total resistance R_eq = 1 / (1/R1 + 1/R2 + 1/R3) = 1 / (1/4 + 1/4 + 1/4) = 1.33Ω. Current I = V / R_eq = 12V / 1.33Ω ≈ 9A.
Correct Answer: B — 4A
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Q. What is the total current in a circuit with a 24V battery and three resistors (2Ω, 4Ω, and 6Ω) connected in series?
Solution
Total resistance R = R1 + R2 + R3 = 2Ω + 4Ω + 6Ω = 12Ω. Using Ohm's law, I = V/R = 24V / 12Ω = 2A.
Correct Answer: B — 3A
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Q. What is the total power consumed in a circuit with a current of 5A and a total resistance of 4Ω?
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A.
10W
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B.
20W
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C.
30W
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D.
40W
Solution
Power (P) = I^2 * R = 5^2 * 4 = 25 * 4 = 100W.
Correct Answer: D — 40W
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