Amperes Law
Q. In a solenoid carrying current, the magnetic field inside the solenoid is:
A.
Zero
B.
Uniform and directed along the axis
C.
Non-uniform and directed radially
D.
Variable and depends on the distance from the center
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Solution
Inside a long solenoid, the magnetic field is uniform and directed along the axis of the solenoid.
Correct Answer: B — Uniform and directed along the axis
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Q. In a solenoid carrying current, what is the direction of the magnetic field inside the solenoid?
A.
Perpendicular to the axis of the solenoid
B.
Along the axis of the solenoid
C.
Radially outward from the solenoid
D.
Zero inside the solenoid
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Solution
The magnetic field inside a solenoid is uniform and directed along the axis of the solenoid.
Correct Answer: B — Along the axis of the solenoid
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Q. In a solenoid carrying current, what is the direction of the magnetic field inside the solenoid according to Ampere's Law?
A.
From south to north
B.
From north to south
C.
Perpendicular to the axis
D.
Radially outward
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Solution
The magnetic field inside a solenoid is directed from the north pole to the south pole of the solenoid.
Correct Answer: B — From north to south
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Q. In a solenoid, what is the expression for the magnetic field inside it when it carries a current I?
A.
B = μ₀nI
B.
B = μ₀I/2πr
C.
B = μ₀I/4πr²
D.
B = μ₀I/n
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Solution
Inside a long solenoid, the magnetic field is given by B = μ₀nI, where n is the number of turns per unit length.
Correct Answer: A — B = μ₀nI
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Q. In a toroidal solenoid with N turns and carrying current I, what is the magnetic field inside the toroid?
A.
μ₀NI/2πr
B.
μ₀NI/r
C.
μ₀NI/4πr
D.
μ₀NI/2r
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Solution
Using Ampere's Law, B = μ₀NI/2πr inside a toroidal solenoid.
Correct Answer: B — μ₀NI/r
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Q. In a toroidal solenoid, how does the magnetic field strength depend on the number of turns per unit length?
A.
Directly proportional
B.
Inversely proportional
C.
Independent
D.
Exponential relation
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Solution
The magnetic field strength in a toroidal solenoid is directly proportional to the number of turns per unit length.
Correct Answer: A — Directly proportional
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Q. In a toroidal solenoid, the magnetic field inside the toroid is:
A.
Uniform and zero
B.
Uniform and non-zero
C.
Non-uniform and zero
D.
Non-uniform and non-zero
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Solution
The magnetic field inside a toroidal solenoid is uniform and non-zero, depending on the current and the number of turns.
Correct Answer: B — Uniform and non-zero
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Q. In a toroidal solenoid, what is the expression for the magnetic field inside the toroid?
A.
B = μ₀nI
B.
B = μ₀I/2πr
C.
B = μ₀I/n
D.
B = μ₀I/4πr²
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Solution
The magnetic field inside a toroidal solenoid is given by B = μ₀nI, where n is the number of turns per unit length along the circular path.
Correct Answer: A — B = μ₀nI
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Q. In a toroidal solenoid, what is the magnetic field inside the toroid?
A.
0
B.
μ₀nI
C.
μ₀I/2πr
D.
μ₀I/n
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Solution
The magnetic field inside a toroidal solenoid is given by B = μ₀nI.
Correct Answer: B — μ₀nI
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Q. What does Ampere's Law relate to in electromagnetism?
A.
Electric field and charge
B.
Magnetic field and current
C.
Electric potential and capacitance
D.
Magnetic flux and resistance
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Solution
Ampere's Law states that the magnetic field around a closed loop is proportional to the electric current passing through the loop.
Correct Answer: B — Magnetic field and current
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Q. What happens to the magnetic field inside a solenoid if the current is reversed?
A.
Reverses direction
B.
Increases
C.
Decreases
D.
Remains the same
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Solution
Reversing the current reverses the direction of the magnetic field.
Correct Answer: A — Reverses direction
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Q. What happens to the magnetic field strength if the current in a solenoid is halved?
A.
Doubles
B.
Halves
C.
Remains the same
D.
Quadruples
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Solution
The magnetic field strength is directly proportional to the current, so it halves.
Correct Answer: B — Halves
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Q. What is the direction of the magnetic field around a current-carrying wire as per the right-hand rule?
A.
Clockwise
B.
Counterclockwise
C.
Radial
D.
Tangential
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Solution
According to the right-hand rule, if you point your thumb in the direction of the current, your fingers curl in the direction of the magnetic field lines, which is counterclockwise.
Correct Answer: B — Counterclockwise
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Q. What is the direction of the magnetic field around a current-carrying wire?
A.
Radially inward
B.
Radially outward
C.
Clockwise or counterclockwise depending on current direction
D.
Perpendicular to the wire
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Solution
The direction of the magnetic field around a current-carrying wire is determined by the right-hand rule, which gives a clockwise or counterclockwise direction based on the current's direction.
Correct Answer: C — Clockwise or counterclockwise depending on current direction
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Q. What is the direction of the magnetic field around a straight conductor carrying current, as per the right-hand rule?
A.
Clockwise
B.
Counterclockwise
C.
Radially inward
D.
Radially outward
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Solution
Using the right-hand rule, if you point your thumb in the direction of the current, your fingers curl in the direction of the magnetic field, which is counterclockwise.
Correct Answer: B — Counterclockwise
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Q. What is the effect of increasing the current in a solenoid on the magnetic field strength?
A.
Decreases the magnetic field strength
B.
Increases the magnetic field strength
C.
Has no effect
D.
Reverses the magnetic field direction
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Solution
Increasing the current in a solenoid increases the magnetic field strength, as B is directly proportional to I.
Correct Answer: B — Increases the magnetic field strength
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Q. What is the effect of increasing the current in a solenoid on the magnetic field strength inside it?
A.
Increases the magnetic field strength
B.
Decreases the magnetic field strength
C.
No effect on the magnetic field strength
D.
Reverses the direction of the magnetic field
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Solution
According to Ampere's Law, increasing the current in a solenoid increases the magnetic field strength inside it.
Correct Answer: A — Increases the magnetic field strength
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Q. What is the effect of increasing the number of turns in a coil on the magnetic field produced?
A.
Increases
B.
Decreases
C.
No effect
D.
Reverses
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Solution
Increasing the number of turns increases the magnetic field strength.
Correct Answer: A — Increases
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Q. What is the effect of increasing the number of turns in a coil on the magnetic field produced by it?
A.
It decreases the magnetic field
B.
It has no effect
C.
It increases the magnetic field
D.
It reverses the magnetic field direction
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Solution
Increasing the number of turns in a coil increases the magnetic field produced, as the field is proportional to the number of turns.
Correct Answer: C — It increases the magnetic field
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Q. What is the effect of increasing the radius of a circular loop carrying current on the magnetic field at its center?
A.
It increases the magnetic field
B.
It decreases the magnetic field
C.
It has no effect
D.
It reverses the direction of the magnetic field
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Solution
The magnetic field at the center of a circular loop is inversely proportional to the radius; thus, increasing the radius decreases the magnetic field.
Correct Answer: B — It decreases the magnetic field
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Q. What is the effect of increasing the radius of a circular loop on the magnetic field at its center?
A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
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Solution
The magnetic field at the center of a circular loop decreases as the radius increases.
Correct Answer: B — Decreases
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Q. What is the integral form of Ampere's Law?
A.
∮B·dl = μ₀I_enclosed
B.
∮E·dl = -dΦ/dt
C.
∮F·dl = m*a
D.
∮V·dl = Q/C
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Solution
The integral form of Ampere's Law states that the line integral of the magnetic field B around a closed loop is equal to μ₀ times the enclosed current I.
Correct Answer: A — ∮B·dl = μ₀I_enclosed
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Q. What is the magnetic field at a distance r from an infinitely long straight wire carrying current I?
A.
μ₀I/2πr
B.
μ₀I/4πr
C.
μ₀I/πr
D.
0
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Solution
Using Ampere's Law, B = μ₀I/2πr for an infinitely long straight wire.
Correct Answer: A — μ₀I/2πr
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Q. What is the magnetic field at the center of a square loop of side a carrying current I?
A.
μ₀I/4a
B.
μ₀I/2a
C.
μ₀I/a
D.
μ₀I/8a
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Solution
The magnetic field at the center of a square loop is B = μ₀I/4a.
Correct Answer: A — μ₀I/4a
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Q. What is the magnetic field due to a current loop at a point on its axis?
A.
μ₀I/2R
B.
μ₀I/4R
C.
μ₀I/2R²
D.
μ₀I/4R²
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Solution
Using Ampere's Law, B = μ₀I/2R² at a point on the axis of a current loop.
Correct Answer: C — μ₀I/2R²
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Q. What is the magnetic field due to a long straight wire carrying current I at a distance r from the wire?
A.
μ₀I/2πr
B.
μ₀I/4πr
C.
μ₀I/πr
D.
μ₀I/8πr
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Solution
The magnetic field due to a long straight wire is given by B = (μ₀I)/(2πr).
Correct Answer: A — μ₀I/2πr
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Q. What is the magnetic field due to a solenoid of length L, carrying n turns per unit length and current I?
A.
μ₀nI
B.
μ₀nI/L
C.
μ₀nI/2
D.
μ₀nI/L²
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Solution
The magnetic field inside a long solenoid is B = μ₀nI.
Correct Answer: A — μ₀nI
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Q. What is the magnetic field inside a hollow cylindrical shell carrying current I?
A.
0
B.
μ₀I/2πR
C.
μ₀I/4πR
D.
μ₀I/πR
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Solution
Inside a hollow cylindrical shell, the magnetic field is zero.
Correct Answer: A — 0
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Q. What is the magnetic field inside a long straight conductor carrying a current I?
A.
0
B.
μ₀I/2πr
C.
μ₀I/4πr
D.
μ₀I/πr
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Solution
Using Ampere's Law, B = μ₀I/2πr for a long straight conductor.
Correct Answer: B — μ₀I/2πr
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Q. What is the magnetic field inside a long straight conductor carrying current I?
A.
0
B.
μ₀I/2πr
C.
μ₀I/4πr
D.
μ₀I/πr
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Solution
Using Ampere's Law, B = μ₀I/2πr for a long straight conductor.
Correct Answer: B — μ₀I/2πr
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