According to Kepler's third law, increasing the altitude of a satellite increases its orbital period.

Increasing the height of a satellite decreases its orbital speed, as the gravitational force acting on it decreases.

If the orbital speed is to remain constant, increasing the mass of the satellite requires an increase in the orbital radius due to the balance of gravitational and centripetal forces.

The mass of the satellite does not affect the orbital radius if the speed is constant, as the gravitational force and centripetal force balance each other.

The mass of the satellite does not affect its orbital radius; it is determined by the mass of the Earth and the orbital speed.

The orbital speed of a satellite depends on the mass of the Earth and the radius of the orbit, but not on the mass of the satellite itself. Therefore, increasing the mass of the satellite has no effect on its orbital speed.

Increasing the mass of either or both objects increases the gravitational force between them.

The escape velocity from the Earth's surface is approximately 11.2 km/s.

The escape velocity from the Earth's surface is approximately 11.2 km/s.

The escape velocity from the Earth's surface is approximately 11.2 km/s.

Escape velocity v = √(2GM/R); here, v = √(2 * 4GM / 3R) = √(8GM/3R).

Escape velocity v = √(2GM/R) = √(2 * 2M / 4R) = √(8GM/4R) = √(8GM/R)

Escape velocity is given by v = √(2GM/R).

The escape velocity from the surface of the Earth is approximately 11.2 km/s.

Escape velocity (v) = sqrt(2gR) = sqrt(2 * 9.8 * 6.4 x 10^6) ≈ 11.2 km/s.

Inside a uniform sphere, the gravitational field strength varies linearly with distance from the center, so at R/2 it is g/2.

g = GM/r²; at 3R, g = GM/(3R)² = G/9.

g = GM/r², at 3R, g = GM/(3R)² = GM/9R².

Gravitational field strength (g') = g / (distance^2) = g / (3R)^2 = g / 9.

Gravitational field strength g = GM/r². At 4R, g = GM/(4R)² = GM/16R² = G/16.

g = GM/r²; at 4R, g = GM/(4R)² = GM/16R².

The gravitational field strength g at the surface of a planet is given by g = GM/R^2.

g = GM/R² = (6.67 x 10^-11 * 6 x 10^24) / (6.4 x 10^6)² = 9.8 N/kg

The gravitational field strength at the surface of the Earth is approximately 9.8 N/kg.

F = mg = 1 * 9.8 = 9.8 N.

F = mg = 10 kg * 9.8 m/s^2 = 98 N.

Using F = mg, where m = 10 kg and g = 9.8 m/s², F = 10 * 9.8 = 98 N.

F = mg = 10 * 9.8 = 98 N

Weight W = m * g = 70 kg * 9.8 m/s² = 686 N

The gravitational force acting on a satellite in orbit is given by F = GmM/(R+h)^2, where R is the radius of the Earth.