Current Electricity Study Materials for Competitive Exams

Current Electricity

Circuits & Kirchhoff Laws Ohms Law Potentiometer Resistivity Wheatstone Bridge

Q. If a 6Ω resistor is connected to a 9V battery, what is the power dissipated by the resistor?

A. 6W
B. 9W
C. 12W
D. 15W

Solution

Power P = V^2 / R = (9V)^2 / 6Ω = 81 / 6 = 13.5W.

Correct Answer: C — 12W

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Q. If a 9V battery is connected to a 3Ω resistor, what is the power consumed by the resistor?

A. 3W
B. 9W
C. 27W
D. 1W

Solution

Power P = V^2/R = (9V)^2 / 3Ω = 81/3 = 27W.

Correct Answer: B — 9W

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Q. If a battery provides a voltage of 9 V and is connected to a circuit with a total resistance of 3 ohms, what is the power consumed by the circuit?

A. 27 W
B. 18 W
C. 9 W
D. 3 W

Solution

Power P = V^2 / R. Here, P = 9^2 / 3 = 81 / 3 = 27 W.

Correct Answer: B — 18 W

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Q. If a circuit contains a 12V battery and two resistors in series of 3Ω and 9Ω, what is the current flowing through the circuit?

A. 0.5A
B. 1A
C. 1.5A
D. 2A

Solution

Total resistance R = R1 + R2 = 3Ω + 9Ω = 12Ω. Using Ohm's law, I = V/R = 12V/12Ω = 1A.

Correct Answer: B — 1A

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Q. If a circuit contains a 9V battery and three resistors (R1 = 3Ω, R2 = 3Ω, R3 = 3Ω) in parallel, what is the total current supplied by the battery?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

The equivalent resistance for resistors in parallel is 1/R_total = 1/R1 + 1/R2 + 1/R3 = 1/3 + 1/3 + 1/3 = 1Ω. The total current is I = V/R_total = 9V / 1Ω = 9A.

Correct Answer: C — 3A

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Q. If a circuit has a 10V source and a total resistance of 5Ω, what is the total current in the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Using Ohm's law, I = V/R = 10V / 5Ω = 2A.

Correct Answer: B — 2A

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Q. If a circuit has a 12V battery and two resistors of 3Ω and 6Ω in series, what is the total current flowing through the circuit?

A. 1A
B. 2A
C. 3A
D. 4A

Solution

Total resistance R = R1 + R2 = 3Ω + 6Ω = 9Ω. Using Ohm's law, I = V/R = 12V / 9Ω = 1.33A.

Correct Answer: B — 2A

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Q. If a circuit has a 12V battery and two resistors of 4 ohms and 8 ohms in series, what is the voltage across the 8 ohm resistor?

A. 4 V
B. 8 V
C. 6 V
D. 12 V

Solution

The total resistance is 4 + 8 = 12 ohms. The current is I = V/R = 12V / 12 ohms = 1 A. The voltage across the 8 ohm resistor is V = I * R = 1 A * 8 ohms = 8 V.

Correct Answer: B — 8 V

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Q. If a circuit has a 15V battery and two resistors (5Ω and 10Ω) in series, what is the voltage across the 10Ω resistor?

A. 5V
B. 10V
C. 15V
D. 0V

Solution

Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (10 / (5 + 10)) * 15 = 10V.

Correct Answer: B — 10V

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Q. If a circuit has a 15V battery and two resistors (R1 = 5Ω, R2 = 10Ω) in series, what is the voltage across R2?

A. 10V
B. 5V
C. 15V
D. 0V

Solution

Voltage across R2 = (R2 / (R1 + R2)) * V = (10Ω / (5Ω + 10Ω)) * 15V = 10V.

Correct Answer: A — 10V

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Q. If a circuit has a 15V battery and two resistors of 5Ω and 10Ω in series, what is the power dissipated by the 10Ω resistor?

A. 1.5W
B. 2.5W
C. 3.75W
D. 5W

Solution

Total resistance R = 5Ω + 10Ω = 15Ω. Current I = V/R = 15V/15Ω = 1A. Power P = I^2 * R = 1^2 * 10 = 10W.

Correct Answer: C — 3.75W

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Q. If a circuit has a 24V battery and two resistors of 6Ω and 12Ω in series, what is the voltage across the 12Ω resistor?

A. 8V
B. 12V
C. 16V
D. 18V

Solution

Using the voltage divider rule, V2 = (R2 / (R1 + R2)) * Vtotal = (12 / (6 + 12)) * 24 = 16V.

Correct Answer: B — 12V

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Q. If a circuit has a 9V battery and two resistors of 3Ω and 6Ω in series, what is the voltage across the 6Ω resistor?

A. 3V
B. 6V
C. 9V
D. 4.5V

Solution

Using the voltage divider rule, V6Ω = (R6Ω / (R3Ω + R6Ω)) * Vtotal = (6 / (3 + 6)) * 9 = 6V.

Correct Answer: B — 6V

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Q. If a circuit has a current of 0.5 A and a resistance of 20 ohms, what is the voltage?

A. 10 V
B. 5 V
C. 15 V
D. 20 V

Solution

Using Ohm's Law, V = I * R = 0.5 A * 20 Ω = 10 V.

Correct Answer: A — 10 V

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Q. If a circuit has a current of 2 A flowing through a resistor of 5 ohms, what is the voltage across the resistor?

A. 5 V
B. 10 V
C. 2 V
D. 1 V

Solution

Using Ohm's Law, V = I * R. Here, V = 2 A * 5 ohms = 10 V.

Correct Answer: B — 10 V

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Q. If a circuit has a current of 2A flowing through a 5Ω resistor, what is the power dissipated by the resistor?

A. 5W
B. 10W
C. 15W
D. 20W

Solution

Power (P) = I^2 * R = (2^2) * 5 = 4 * 5 = 20W.

Correct Answer: B — 10W

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Q. If a circuit has a current of 2A flowing through a 5Ω resistor, what is the voltage across the resistor?

A. 10V
B. 5V
C. 2.5V
D. 1V

Solution

Using Ohm's Law, V = I * R = 2A * 5Ω = 10V.

Correct Answer: A — 10V

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Q. If a circuit has a current of 3 A and a resistance of 4 ohms, what is the voltage across the circuit?

A. 7 V
B. 12 V
C. 15 V
D. 20 V

Solution

Using Ohm's Law, V = IR = 3 A * 4 Ω = 12 V.

Correct Answer: B — 12 V

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Q. If a circuit has a current of 3A flowing through a 10Ω resistor, what is the power dissipated by the resistor?

A. 30W
B. 10W
C. 90W
D. 15W

Solution

Power (P) = I^2 * R = 3^2 * 10 = 9 * 10 = 90W.

Correct Answer: A — 30W

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Q. If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated in the resistor?

A. 15W
B. 9W
C. 5W
D. 3W

Solution

Power (P) = I^2 * R = (3A)^2 * 5Ω = 9A^2 * 5Ω = 45W.

Correct Answer: A — 15W

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Q. If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated by the resistor?

A. 5W
B. 10W
C. 15W
D. 20W

Solution

Power (P) = I^2 * R = (3A)^2 * 5Ω = 9 * 5 = 45W.

Correct Answer: C — 15W

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Q. If a circuit has a current of 5 A and a resistance of 10 Ω, what is the power consumed in the circuit?

A. 50 W
B. 25 W
C. 10 W
D. 5 W

Solution

Power (P) can be calculated using P = I^2 * R = (5 A)^2 * 10 Ω = 25 A^2 * 10 Ω = 250 W.

Correct Answer: A — 50 W

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Q. If a circuit has a current of 5 A and a resistance of 10 Ω, what is the voltage?

A. 50 V
B. 5 V
C. 10 V
D. 15 V

Solution

Using Ohm's Law, V = I * R = 5 A * 10 Ω = 50 V.

Correct Answer: A — 50 V

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Q. If a circuit has a current of 5 amperes and a resistance of 10 ohms, what is the voltage?

A. 50 volts
B. 5 volts
C. 10 volts
D. 15 volts

Solution

Using Ohm's Law, V = I * R = 5 A * 10 Ω = 50 V.

Correct Answer: A — 50 volts

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Q. If a circuit has a current of 5A flowing through a 10Ω resistor, what is the power dissipated by the resistor?

A. 25W
B. 50W
C. 75W
D. 100W

Solution

Power (P) = I^2 * R = 5^2 * 10 = 25 * 10 = 250W.

Correct Answer: B — 50W

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Q. If a circuit has a current of 5A flowing through a resistor of 10Ω, what is the voltage across the resistor?

A. 5V
B. 10V
C. 15V
D. 50V

Solution

Using Ohm's Law (V = IR), the voltage is V = 5A * 10Ω = 50V.

Correct Answer: B — 10V

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Q. If a circuit has a total current of 3 A and a total resistance of 6 ohms, what is the voltage supplied by the battery?

A. 9 V
B. 6 V
C. 3 V
D. 12 V

Solution

Using Ohm's law, V = I * R, we have V = 3 A * 6 ohms = 18 V.

Correct Answer: A — 9 V

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Q. If a circuit has a total current of 5 A and a total resistance of 10 ohms, what is the voltage across the circuit?

A. 50 V
B. 5 V
C. 10 V
D. 2 V

Solution

Using Ohm's law, V = I * R, we have V = 5 A * 10 ohms = 50 V.

Correct Answer: A — 50 V

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Q. If a circuit has a total current of 5A and a total resistance of 10Ω, what is the total voltage supplied by the battery?

A. 25V
B. 50V
C. 75V
D. 100V

Solution

Using Ohm's Law, V = I * R = 5A * 10Ω = 50V.

Correct Answer: B — 50V

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Q. If a circuit has a total resistance of 10 ohms and a total voltage of 50V, what is the total current?

A. 5 A
B. 10 A
C. 2 A
D. 0.5 A

Solution

Using Ohm's law, I = V/R = 50V / 10 ohms = 5 A.

Correct Answer: A — 5 A

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Current Electricity

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