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What is the value of q for which the function f(x) = { 5 - q, x < 1; 3x + 2, x >= 1 } is continuous at x = 1?

Practice Questions

1 question
Q1
What is the value of q for which the function f(x) = { 5 - q, x < 1; 3x + 2, x >= 1 } is continuous at x = 1?
  1. 0
  2. 1
  3. 2
  4. 3

Questions & Step-by-step Solutions

1 item
Q
Q: What is the value of q for which the function f(x) = { 5 - q, x < 1; 3x + 2, x >= 1 } is continuous at x = 1?
Solution: Setting the two pieces equal at x = 1: 5 - q = 3(1) + 2. Solving gives q = 0.
Steps: 0

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