What is the primary product when 1-bromo-2-methylpropane reacts with KOH in ethanol?
Practice Questions
1 question
Q1
What is the primary product when 1-bromo-2-methylpropane reacts with KOH in ethanol?
2-methylpropene
1-methylpropene
2-bromopropane
no reaction
The reaction leads to the formation of 2-methylpropene through an elimination reaction.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the primary product when 1-bromo-2-methylpropane reacts with KOH in ethanol?
Solution: The reaction leads to the formation of 2-methylpropene through an elimination reaction.
Steps: 6
Step 1: Identify the reactant, which is 1-bromo-2-methylpropane. This compound has a bromine atom attached to a carbon chain.
Step 2: Recognize that KOH (potassium hydroxide) in ethanol is a strong base that can promote elimination reactions.
Step 3: Understand that in an elimination reaction, the bromine atom (leaving group) and a hydrogen atom from an adjacent carbon are removed.
Step 4: Determine which hydrogen atom will be removed. In this case, the hydrogen from the carbon adjacent to the one with the bromine will be removed.
Step 5: After the elimination of the bromine and the hydrogen, a double bond forms between the two carbons, resulting in the product.
Step 6: The final product is 2-methylpropene, which has a double bond between the second and third carbons of the chain.
