What is the potential difference between two points in an electric field if the electric field strength is 50 N/C and the distance between the points is 0.4 m? (2023)
Practice Questions
1 question
Q1
What is the potential difference between two points in an electric field if the electric field strength is 50 N/C and the distance between the points is 0.4 m? (2023)
20 V
10 V
5 V
2 V
Potential difference V = E * d = 50 N/C * 0.4 m = 20 V.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the potential difference between two points in an electric field if the electric field strength is 50 N/C and the distance between the points is 0.4 m? (2023)
Solution: Potential difference V = E * d = 50 N/C * 0.4 m = 20 V.
