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What is the order of a reaction if the rate law is given by rate = k[A]^2[B]?
What is the order of a reaction if the rate law is given by rate = k[A]^2[B]?
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What is the order of a reaction if the rate law is given by rate = k[A]^2[B]?
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The order of the reaction is the sum of the exponents in the rate law. Here, it is 2 (from [A]^2) + 1 (from [B]) = 3.
Questions & Step-by-step Solutions
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Q: What is the order of a reaction if the rate law is given by rate = k[A]^2[B]?
Solution:
The order of the reaction is the sum of the exponents in the rate law. Here, it is 2 (from [A]^2) + 1 (from [B]) = 3.
Steps: 5
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Step 1: Identify the rate law given in the question, which is rate = k[A]^2[B].
Step 2: Look at the exponents of the concentration terms in the rate law.
Step 3: The exponent for [A] is 2, and the exponent for [B] is 1.
Step 4: Add the exponents together: 2 (from [A]^2) + 1 (from [B]) = 3.
Step 5: The total sum of the exponents gives you the order of the reaction.
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