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What is the Nernst equation for a half-reaction involving 2 electrons at 25°C?
What is the Nernst equation for a half-reaction involving 2 electrons at 25°C?
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Practice Questions
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Q1
What is the Nernst equation for a half-reaction involving 2 electrons at 25°C?
E = E° - 0.059/n log(Q)
E = E° + 0.059/n log(Q)
E = E° - 0.0257/n log(Q)
E = E° + 0.0257/n log(Q)
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The Nernst equation is E = E° - (0.059/n)log(Q) at 25°C.
Questions & Step-by-step Solutions
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Q
Q: What is the Nernst equation for a half-reaction involving 2 electrons at 25°C?
Solution:
The Nernst equation is E = E° - (0.059/n)log(Q) at 25°C.
Steps: 7
Show Steps
Step 1: Understand that the Nernst equation helps calculate the cell potential (E) under non-standard conditions.
Step 2: Know that the standard cell potential (E°) is the potential under standard conditions.
Step 3: Identify that 'n' is the number of electrons transferred in the half-reaction. In this case, n = 2.
Step 4: Recognize that Q is the reaction quotient, which is a measure of the concentrations of the reactants and products.
Step 5: Write down the Nernst equation: E = E° - (0.059/n)log(Q).
Step 6: Substitute n = 2 into the equation: E = E° - (0.059/2)log(Q).
Step 7: Simplify the equation to E = E° - 0.0295log(Q) for the specific case of 2 electrons at 25°C.
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