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What is the molality of a solution containing 3 moles of solute in 500 g of solv
What is the molality of a solution containing 3 moles of solute in 500 g of solvent? (2021)
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Practice Questions
1 question
Q1
What is the molality of a solution containing 3 moles of solute in 500 g of solvent? (2021)
6 m
3 m
1.5 m
0.5 m
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Molality (m) = moles of solute / kg of solvent = 3 moles / 0.5 kg = 6 m.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the molality of a solution containing 3 moles of solute in 500 g of solvent? (2021)
Solution:
Molality (m) = moles of solute / kg of solvent = 3 moles / 0.5 kg = 6 m.
Steps: 7
Show Steps
Step 1: Identify the number of moles of solute. In this case, there are 3 moles of solute.
Step 2: Identify the mass of the solvent. Here, the mass of the solvent is 500 grams.
Step 3: Convert the mass of the solvent from grams to kilograms. Since 1000 grams = 1 kilogram, 500 grams is equal to 0.5 kilograms.
Step 4: Use the formula for molality, which is molality (m) = moles of solute / kg of solvent.
Step 5: Plug in the values into the formula: m = 3 moles / 0.5 kg.
Step 6: Calculate the result: 3 divided by 0.5 equals 6.
Step 7: Therefore, the molality of the solution is 6 m.
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