What is the maximum number of iterations needed to find an element in an array of size 32 using binary search?
Practice Questions
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What is the maximum number of iterations needed to find an element in an array of size 32 using binary search?
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The maximum number of iterations is log2(32) = 5, but since we count from 0, it can take up to 6 iterations.
Questions & Step-by-step Solutions
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Q
Q: What is the maximum number of iterations needed to find an element in an array of size 32 using binary search?
Solution: The maximum number of iterations is log2(32) = 5, but since we count from 0, it can take up to 6 iterations.
Steps: 6
Step 1: Understand that binary search works by repeatedly dividing the array in half.
Step 2: Know that the maximum number of iterations needed to find an element is determined by how many times you can divide the array until you reach one element.
Step 3: Calculate log2(32). This means you are finding how many times you can divide 32 by 2 until you get to 1.
Step 4: Calculate log2(32). Since 32 is 2 raised to the power of 5 (because 2^5 = 32), log2(32) = 5.
Step 5: Remember that we start counting from 0. So, if it takes 5 divisions to reach 1, the total number of iterations is 5 + 1 = 6.
Step 6: Conclude that the maximum number of iterations needed to find an element in an array of size 32 using binary search is 6.
