What is the major product of the reaction between 1-bromobutane and sodium ethoxide in ethanol?

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Q: What is the major product of the reaction between 1-bromobutane and sodium ethoxide in ethanol?

Solution: The reaction is an example of an SN2 reaction, where sodium ethoxide acts as a nucleophile, leading to the formation of 1-ethoxybutane.

Steps: 5

Step 1: Identify the reactants. We have 1-bromobutane (a primary alkyl halide) and sodium ethoxide (a strong nucleophile).
Step 2: Recognize the type of reaction. This is an SN2 reaction because 1-bromobutane is a primary halide, which is favorable for SN2.
Step 3: Understand the role of sodium ethoxide. Sodium ethoxide (C2H5O-) will attack the carbon atom that is bonded to the bromine in 1-bromobutane.
Step 4: Describe the nucleophilic attack. The ethoxide ion will replace the bromine atom, forming a new bond with the carbon.
Step 5: Identify the product. The product formed is 1-ethoxybutane, where the ethoxy group (C2H5O-) is now attached to the butane chain.