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What is the equation of the line parallel to y = 2x + 3 that passes through the
What is the equation of the line parallel to y = 2x + 3 that passes through the point (1, 1)?
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Q1
What is the equation of the line parallel to y = 2x + 3 that passes through the point (1, 1)?
y = 2x - 1
y = 2x + 1
y = 2x + 3
y = 2x - 3
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Parallel lines have the same slope: y - 1 = 2(x - 1) => y = 2x - 1.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the equation of the line parallel to y = 2x + 3 that passes through the point (1, 1)?
Solution:
Parallel lines have the same slope: y - 1 = 2(x - 1) => y = 2x - 1.
Steps: 6
Show Steps
Step 1: Identify the slope of the given line. The equation is y = 2x + 3, so the slope (m) is 2.
Step 2: Since parallel lines have the same slope, the slope of the new line will also be 2.
Step 3: Use the point-slope form of the equation of a line, which is y - y1 = m(x - x1). Here, (x1, y1) is the point (1, 1) and m is 2.
Step 4: Substitute the values into the point-slope form: y - 1 = 2(x - 1).
Step 5: Simplify the equation. Distribute the 2: y - 1 = 2x - 2.
Step 6: Add 1 to both sides to solve for y: y = 2x - 1.
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