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What is the energy of a photon with a frequency of 5 x 10^14 Hz? (Planck's const
What is the energy of a photon with a frequency of 5 x 10^14 Hz? (Planck's constant h = 6.626 x 10^-34 J·s) (2021)
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Practice Questions
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Q1
What is the energy of a photon with a frequency of 5 x 10^14 Hz? (Planck's constant h = 6.626 x 10^-34 J·s) (2021)
3.31 x 10^-19 J
1.32 x 10^-19 J
2.48 x 10^-19 J
4.97 x 10^-19 J
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Energy (E) = h * frequency = 6.626 x 10^-34 J·s * 5 x 10^14 Hz = 3.31 x 10^-19 J.
Questions & Step-by-step Solutions
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Q
Q: What is the energy of a photon with a frequency of 5 x 10^14 Hz? (Planck's constant h = 6.626 x 10^-34 J·s) (2021)
Solution:
Energy (E) = h * frequency = 6.626 x 10^-34 J·s * 5 x 10^14 Hz = 3.31 x 10^-19 J.
Steps: 6
Show Steps
Step 1: Identify the formula to calculate the energy of a photon, which is E = h * frequency.
Step 2: Write down the value of Planck's constant (h), which is 6.626 x 10^-34 J·s.
Step 3: Write down the frequency of the photon, which is 5 x 10^14 Hz.
Step 4: Substitute the values into the formula: E = (6.626 x 10^-34 J·s) * (5 x 10^14 Hz).
Step 5: Perform the multiplication: 6.626 x 5 = 33.13 and combine the powers of 10: 10^-34 * 10^14 = 10^-20.
Step 6: Combine the results: E = 33.13 x 10^-20 J, which can be simplified to 3.31 x 10^-19 J.
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