What is the energy of a photon emitted when an electron transitions from n=3 to n=2 in a hydrogen atom? (2019)
Practice Questions
1 question
Q1
What is the energy of a photon emitted when an electron transitions from n=3 to n=2 in a hydrogen atom? (2019)
1.89 eV
3.40 eV
10.20 eV
12.09 eV
The energy difference can be calculated using the formula E = 13.6 eV (1/n1² - 1/n2²). For n1=2 and n2=3, E = 13.6 eV (1/2² - 1/3²) = 1.89 eV.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the energy of a photon emitted when an electron transitions from n=3 to n=2 in a hydrogen atom? (2019)
Solution: The energy difference can be calculated using the formula E = 13.6 eV (1/n1² - 1/n2²). For n1=2 and n2=3, E = 13.6 eV (1/2² - 1/3²) = 1.89 eV.
