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What is the axis of symmetry for the parabola given by the equation y = 3x^2 + 6
What is the axis of symmetry for the parabola given by the equation y = 3x^2 + 6x + 2?
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Practice Questions
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Q1
What is the axis of symmetry for the parabola given by the equation y = 3x^2 + 6x + 2?
x = -1
y = -1
x = 1
y = 1
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The axis of symmetry for a parabola in the form y = ax^2 + bx + c is given by x = -b/(2a). Here, a = 3 and b = 6, so x = -6/(2*3) = -1.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the axis of symmetry for the parabola given by the equation y = 3x^2 + 6x + 2?
Solution:
The axis of symmetry for a parabola in the form y = ax^2 + bx + c is given by x = -b/(2a). Here, a = 3 and b = 6, so x = -6/(2*3) = -1.
Steps: 7
Show Steps
Step 1: Identify the coefficients a and b from the equation y = 3x^2 + 6x + 2. Here, a = 3 and b = 6.
Step 2: Use the formula for the axis of symmetry, which is x = -b/(2a).
Step 3: Substitute the values of a and b into the formula: x = -6/(2*3).
Step 4: Calculate the denominator: 2*3 = 6.
Step 5: Now substitute back: x = -6/6.
Step 6: Simplify the fraction: x = -1.
Step 7: The axis of symmetry for the parabola is x = -1.
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