John starts from point A and walks 30 meters East, then 40 meters North. How far is he from point A? (2023)

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Q: John starts from point A and walks 30 meters East, then 40 meters North. How far is he from point A? (2023)

Solution: Using the Pythagorean theorem, the distance from point A is √(30^2 + 40^2) = 50 meters.

Steps: 8

Step 1: Understand that John walks 30 meters East and then 40 meters North.
Step 2: Visualize John's path as a right triangle, where one side is 30 meters (East) and the other side is 40 meters (North).
Step 3: Use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the distance from point A) is equal to the sum of the squares of the other two sides.
Step 4: Calculate the square of the East distance: 30^2 = 900.
Step 5: Calculate the square of the North distance: 40^2 = 1600.
Step 6: Add the two squares together: 900 + 1600 = 2500.
Step 7: Take the square root of the sum to find the distance: √2500 = 50 meters.
Step 8: Conclude that John is 50 meters away from point A.