In the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O, what is being oxidized? (2019)

Practice Questions

1 question
Q1
In the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O, what is being oxidized? (2019)
  1. MnO4-
  2. C2O4^2-
  3. H+
  4. CO2

Questions & Step-by-step Solutions

1 item
Q
Q: In the reaction 2MnO4- + 5C2O4^2- + 16H+ → 2Mn^2+ + 10CO2 + 8H2O, what is being oxidized? (2019)
Solution: C2O4^2- (oxalate ion) is being oxidized to CO2 in this reaction.
Steps: 0

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