In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced from 4 moles of Fe?
Practice Questions
1 question
Q1
In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced from 4 moles of Fe?
315.5 g
267 g
200 g
150 g
4 moles of Fe produce 4 moles of FeCl3. Mass of FeCl3 = 4 moles * 162.5 g/mole = 650 g.
Questions & Step-by-step Solutions
1 item
Q
Q: In the reaction 2Fe + 3Cl2 → 2FeCl3, how many grams of FeCl3 can be produced from 4 moles of Fe?
Solution: 4 moles of Fe produce 4 moles of FeCl3. Mass of FeCl3 = 4 moles * 162.5 g/mole = 650 g.
Steps: 7
Step 1: Identify the reaction: 2Fe + 3Cl2 → 2FeCl3.
Step 2: Understand that 2 moles of Fe produce 2 moles of FeCl3.
Step 3: Calculate how many moles of FeCl3 can be produced from 4 moles of Fe. Since 2 moles of Fe produce 2 moles of FeCl3, then 4 moles of Fe will produce 4 moles of FeCl3.
Step 4: Find the molar mass of FeCl3. The molar mass is calculated as follows: Fe (55.85 g/mol) + 3 * Cl (35.45 g/mol) = 55.85 + 106.35 = 162.2 g/mol.
Step 5: Calculate the mass of FeCl3 produced using the formula: mass = moles * molar mass. Here, mass = 4 moles * 162.2 g/mol.
Step 6: Perform the multiplication: 4 * 162.2 = 648.8 g.
Step 7: Round the answer if necessary. The final mass of FeCl3 produced is approximately 650 g.
