In the electrochemical series, which element is the strongest oxidizing agent? (2023)
Practice Questions
1 question
Q1
In the electrochemical series, which element is the strongest oxidizing agent? (2023)
Li
F2
Na
K
Fluorine (F2) is the strongest oxidizing agent in the electrochemical series due to its high electronegativity and tendency to gain electrons.
Questions & Step-by-step Solutions
1 item
Q
Q: In the electrochemical series, which element is the strongest oxidizing agent? (2023)
Solution: Fluorine (F2) is the strongest oxidizing agent in the electrochemical series due to its high electronegativity and tendency to gain electrons.
Steps: 6
Step 1: Understand what an oxidizing agent is. An oxidizing agent is a substance that can gain electrons and cause another substance to be oxidized.
Step 2: Learn about the electrochemical series. This is a list of elements arranged by their ability to gain electrons.
Step 3: Identify the element with the highest tendency to gain electrons in the electrochemical series.
Step 4: Recognize that fluorine (F2) is at the top of the electrochemical series.
Step 5: Understand that fluorine has high electronegativity, meaning it strongly attracts electrons.
Step 6: Conclude that because of its position in the series and its properties, fluorine is the strongest oxidizing agent.
