In a simple cubic lattice, how many atoms are effectively present in one unit cell? (2019)
Practice Questions
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In a simple cubic lattice, how many atoms are effectively present in one unit cell? (2019)
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In a simple cubic lattice, there is 1 atom effectively present in one unit cell, as each corner atom contributes 1/8th of an atom to the unit cell.
Questions & Step-by-step Solutions
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Q
Q: In a simple cubic lattice, how many atoms are effectively present in one unit cell? (2019)
Solution: In a simple cubic lattice, there is 1 atom effectively present in one unit cell, as each corner atom contributes 1/8th of an atom to the unit cell.
Steps: 6
Step 1: Understand what a simple cubic lattice is. It is a 3D arrangement of atoms where each atom is located at the corners of a cube.
Step 2: Identify how many corners are in a cube. A cube has 8 corners.
Step 3: Know that each corner atom is shared by 8 adjacent unit cells. This means that only a fraction of each corner atom belongs to one unit cell.
Step 4: Calculate the contribution of each corner atom to the unit cell. Since each corner atom contributes 1/8th of an atom, you multiply the number of corners (8) by the contribution of each corner (1/8).
