In a sequence of numbers where each term increases by a constant value, if the first term is 5 and the common difference is 3, what is the 10th term?
Practice Questions
1 question
Q1
In a sequence of numbers where each term increases by a constant value, if the first term is 5 and the common difference is 3, what is the 10th term?
32
35
30
28
The nth term of an AP is given by the formula a + (n-1)d. Here, a = 5, d = 3, and n = 10. Thus, the 10th term = 5 + (10-1) * 3 = 5 + 27 = 32.
Questions & Step-by-step Solutions
1 item
Q
Q: In a sequence of numbers where each term increases by a constant value, if the first term is 5 and the common difference is 3, what is the 10th term?
Solution: The nth term of an AP is given by the formula a + (n-1)d. Here, a = 5, d = 3, and n = 10. Thus, the 10th term = 5 + (10-1) * 3 = 5 + 27 = 32.
Steps: 9
Step 1: Identify the first term of the sequence, which is given as 5.
Step 2: Identify the common difference, which is given as 3.
Step 3: Identify the term number we want to find, which is the 10th term (n = 10).
Step 4: Use the formula for the nth term of an arithmetic sequence: nth term = a + (n-1)d.
Step 5: Substitute the values into the formula: a = 5, n = 10, d = 3.
Step 6: Calculate (n-1): 10 - 1 = 9.
Step 7: Multiply the common difference by (n-1): 3 * 9 = 27.
Step 8: Add the first term to the result: 5 + 27 = 32.
