In a mixture of two liquids, if the first liquid is 60% pure and the second is 80% pure, what is the overall purity if they are mixed in equal volumes?
Practice Questions
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Q1
In a mixture of two liquids, if the first liquid is 60% pure and the second is 80% pure, what is the overall purity if they are mixed in equal volumes?
70%
75%
80%
85%
Overall purity = (60% + 80%) / 2 = 70%.
Questions & Step-by-step Solutions
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Q
Q: In a mixture of two liquids, if the first liquid is 60% pure and the second is 80% pure, what is the overall purity if they are mixed in equal volumes?
