In a double-elimination tournament, a team is eliminated after losing two matches. If there are 8 teams, what is the minimum number of matches needed to declare a winner?
Practice Questions
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Q1
In a double-elimination tournament, a team is eliminated after losing two matches. If there are 8 teams, what is the minimum number of matches needed to declare a winner?
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In a double-elimination tournament, the minimum number of matches needed is 2n - 2, where n is the number of teams. For 8 teams, it is 2(8) - 2 = 14.
Questions & Step-by-step Solutions
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Q
Q: In a double-elimination tournament, a team is eliminated after losing two matches. If there are 8 teams, what is the minimum number of matches needed to declare a winner?
Solution: In a double-elimination tournament, the minimum number of matches needed is 2n - 2, where n is the number of teams. For 8 teams, it is 2(8) - 2 = 14.
