In a certain mixture, the ratio of component X to component Y is 2:3. If the total volume of the mixture is 50 liters, how much of component Y is there?
Practice Questions
1 question
Q1
In a certain mixture, the ratio of component X to component Y is 2:3. If the total volume of the mixture is 50 liters, how much of component Y is there?
20 liters
30 liters
25 liters
15 liters
Total parts = 2 + 3 = 5. Y = (3/5) * 50 = 30 liters.
Questions & Step-by-step Solutions
1 item
Q
Q: In a certain mixture, the ratio of component X to component Y is 2:3. If the total volume of the mixture is 50 liters, how much of component Y is there?
Solution: Total parts = 2 + 3 = 5. Y = (3/5) * 50 = 30 liters.
Steps: 5
Step 1: Understand the ratio of component X to component Y, which is 2:3.
Step 2: Add the parts of the ratio together: 2 (for X) + 3 (for Y) = 5 parts total.
Step 3: Determine how much one part is worth by dividing the total volume of the mixture (50 liters) by the total parts (5): 50 liters / 5 parts = 10 liters per part.
Step 4: Find the amount of component Y by multiplying the number of parts for Y (which is 3) by the value of one part (10 liters): 3 parts * 10 liters/part = 30 liters.
Step 5: Conclude that there are 30 liters of component Y in the mixture.
