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If the moment of inertia of a body is 10 kg m², what is the rotational kinetic e
If the moment of inertia of a body is 10 kg m², what is the rotational kinetic energy when it rotates with an angular velocity of 5 rad/s?
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Q1
If the moment of inertia of a body is 10 kg m², what is the rotational kinetic energy when it rotates with an angular velocity of 5 rad/s?
125 J
50 J
100 J
75 J
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Rotational kinetic energy is given by KE = 1/2 I ω² = 1/2 * 10 * 5² = 125 J.
Questions & Step-by-step Solutions
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Q
Q: If the moment of inertia of a body is 10 kg m², what is the rotational kinetic energy when it rotates with an angular velocity of 5 rad/s?
Solution:
Rotational kinetic energy is given by KE = 1/2 I ω² = 1/2 * 10 * 5² = 125 J.
Steps: 6
Show Steps
Step 1: Identify the formula for rotational kinetic energy, which is KE = 1/2 I ω².
Step 2: Substitute the given moment of inertia (I = 10 kg m²) into the formula.
Step 3: Substitute the given angular velocity (ω = 5 rad/s) into the formula.
Step 4: Calculate ω², which is 5² = 25.
Step 5: Multiply I (10 kg m²) by ω² (25) to get 10 * 25 = 250.
Step 6: Multiply the result by 1/2 to find KE: 1/2 * 250 = 125 J.
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