If the moment of inertia of a body is 10 kg·m² and it is subjected to a torque of 20 N·m, what is the angular acceleration?

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Q: If the moment of inertia of a body is 10 kg·m² and it is subjected to a torque of 20 N·m, what is the angular acceleration?

Solution: Using τ = Iα, we have α = τ/I = 20 N·m / 10 kg·m² = 2 rad/s².

Steps: 6

Step 1: Identify the given values. The moment of inertia (I) is 10 kg·m² and the torque (τ) is 20 N·m.
Step 2: Write down the formula that relates torque, moment of inertia, and angular acceleration. The formula is τ = Iα.
Step 3: Rearrange the formula to solve for angular acceleration (α). This gives us α = τ / I.
Step 4: Substitute the known values into the rearranged formula. This means we will calculate α = 20 N·m / 10 kg·m².
Step 5: Perform the division. Calculate 20 divided by 10, which equals 2.
Step 6: State the final result. The angular acceleration (α) is 2 rad/s².