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If one root of the equation x^2 - 6x + k = 0 is 2, what is the value of k?
If one root of the equation x^2 - 6x + k = 0 is 2, what is the value of k?
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Q1
If one root of the equation x^2 - 6x + k = 0 is 2, what is the value of k?
4
6
8
10
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Using the root, we substitute: 2^2 - 6*2 + k = 0 => 4 - 12 + k = 0 => k = 8.
Questions & Step-by-step Solutions
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Q
Q: If one root of the equation x^2 - 6x + k = 0 is 2, what is the value of k?
Solution:
Using the root, we substitute: 2^2 - 6*2 + k = 0 => 4 - 12 + k = 0 => k = 8.
Steps: 8
Show Steps
Step 1: Start with the equation x^2 - 6x + k = 0.
Step 2: We know that one root of the equation is 2.
Step 3: Substitute 2 into the equation for x: 2^2 - 6*2 + k = 0.
Step 4: Calculate 2^2, which is 4.
Step 5: Calculate -6*2, which is -12.
Step 6: Now the equation looks like: 4 - 12 + k = 0.
Step 7: Simplify 4 - 12, which equals -8. So now we have: -8 + k = 0.
Step 8: To find k, add 8 to both sides of the equation: k = 8.
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