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If a torque of 10 Nm is applied to a body with a moment of inertia of 2 kg·m², w
If a torque of 10 Nm is applied to a body with a moment of inertia of 2 kg·m², what is the angular acceleration? (2022)
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Practice Questions
1 question
Q1
If a torque of 10 Nm is applied to a body with a moment of inertia of 2 kg·m², what is the angular acceleration? (2022)
5 rad/s²
10 rad/s²
2 rad/s²
20 rad/s²
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Using the formula τ = Iα, we have α = τ/I = 10 Nm / 2 kg·m² = 5 rad/s².
Questions & Step-by-step Solutions
1 item
Q
Q: If a torque of 10 Nm is applied to a body with a moment of inertia of 2 kg·m², what is the angular acceleration? (2022)
Solution:
Using the formula τ = Iα, we have α = τ/I = 10 Nm / 2 kg·m² = 5 rad/s².
Steps: 6
Show Steps
Step 1: Understand the formula for torque, which is τ = Iα, where τ is torque, I is moment of inertia, and α is angular acceleration.
Step 2: Identify the values given in the question: torque (τ) is 10 Nm and moment of inertia (I) is 2 kg·m².
Step 3: Rearrange the formula to solve for angular acceleration (α): α = τ / I.
Step 4: Substitute the values into the formula: α = 10 Nm / 2 kg·m².
Step 5: Perform the division: 10 divided by 2 equals 5.
Step 6: Conclude that the angular acceleration (α) is 5 rad/s².
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