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If a resistor has a resistance of 8Ω and the current flowing through it is 4A, w
If a resistor has a resistance of 8Ω and the current flowing through it is 4A, what is the voltage across the resistor? (2022)
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Q1
If a resistor has a resistance of 8Ω and the current flowing through it is 4A, what is the voltage across the resistor? (2022)
32V
16V
8V
4V
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Using Ohm's Law, V = I * R = 4A * 8Ω = 32V.
Questions & Step-by-step Solutions
1 item
Q
Q: If a resistor has a resistance of 8Ω and the current flowing through it is 4A, what is the voltage across the resistor? (2022)
Solution:
Using Ohm's Law, V = I * R = 4A * 8Ω = 32V.
Steps: 5
Show Steps
Step 1: Identify the values given in the problem. We have a resistance (R) of 8 ohms (Ω) and a current (I) of 4 amperes (A).
Step 2: Recall Ohm's Law, which states that Voltage (V) = Current (I) * Resistance (R).
Step 3: Substitute the values into the formula: V = 4A * 8Ω.
Step 4: Calculate the multiplication: 4 * 8 = 32.
Step 5: Conclude that the voltage (V) across the resistor is 32 volts (V).
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