If a plant with genotype Bb is crossed with a plant with genotype bb, what is the expected phenotypic ratio of the offspring?

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Q: If a plant with genotype Bb is crossed with a plant with genotype bb, what is the expected phenotypic ratio of the offspring?

Solution: The cross Bb x bb results in a phenotypic ratio of 1 Bb (dominant) to 1 bb (recessive), which is 1:1.

Steps: 6

Step 1: Identify the genotypes of the parent plants. One plant has genotype Bb (heterozygous) and the other has genotype bb (homozygous recessive).
Step 2: Set up a Punnett square to visualize the possible combinations of alleles from the parents.
Step 3: Fill in the Punnett square. The top row will have B and b (from Bb), and the side will have b and b (from bb).
Step 4: Combine the alleles from the top and side of the Punnett square. This gives you the following combinations: Bb and bb.
Step 5: Count the phenotypes. Bb represents the dominant phenotype, and bb represents the recessive phenotype.
Step 6: Determine the ratio of phenotypes. You have 1 Bb (dominant) and 1 bb (recessive), which gives a ratio of 1:1.