If a plant with genotype AaBb is crossed with another plant of genotype Aabb, what is the probability of obtaining an offspring with genotype Aabb?
Practice Questions
1 question
Q1
If a plant with genotype AaBb is crossed with another plant of genotype Aabb, what is the probability of obtaining an offspring with genotype Aabb?
0%
25%
50%
75%
The cross AaBb x Aabb results in 1/4 Aabb, so the probability of obtaining Aabb is 25%.
Questions & Step-by-step Solutions
1 item
Q
Q: If a plant with genotype AaBb is crossed with another plant of genotype Aabb, what is the probability of obtaining an offspring with genotype Aabb?
Solution: The cross AaBb x Aabb results in 1/4 Aabb, so the probability of obtaining Aabb is 25%.
Steps: 8
Step 1: Identify the genotypes of the parent plants. The first plant has genotype AaBb and the second plant has genotype Aabb.
Step 2: Write down the possible gametes (sperm and egg cells) that each parent can produce. The first plant (AaBb) can produce gametes AB, Ab, aB, and ab. The second plant (Aabb) can produce gametes Ab and ab.
Step 3: Create a Punnett square to visualize the possible combinations of the gametes from both parents. The rows will represent the gametes from the first plant and the columns will represent the gametes from the second plant.
Step 4: Fill in the Punnett square with the combinations of the gametes. The combinations will be: AB (from AaBb) with Ab (from Aabb), AB with ab, Ab with Ab, Ab with ab, aB with Ab, aB with ab, ab with Ab, and ab with ab.
Step 5: Count the number of times the genotype Aabb appears in the Punnett square. In this case, Aabb appears once.
Step 6: Calculate the total number of offspring combinations in the Punnett square. There are 8 combinations total.
Step 7: Determine the probability of obtaining the genotype Aabb by dividing the number of Aabb combinations by the total combinations. This gives us 1/8.
Step 8: Convert the fraction to a percentage. 1/8 is equal to 12.5%, not 25%.
