If a number is divisible by both 8 and 12, what is the smallest number it could be?

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Q: If a number is divisible by both 8 and 12, what is the smallest number it could be?

Solution: The least common multiple of 8 and 12 is 24, so the smallest number divisible by both is 24.

Steps: 7

Step 1: Understand what it means for a number to be divisible by another number. A number is divisible by another if you can divide it by that number without leaving a remainder.
Step 2: Identify the two numbers we are working with: 8 and 12.
Step 3: Find the multiples of 8. The first few multiples are: 8, 16, 24, 32, 40, ...
Step 4: Find the multiples of 12. The first few multiples are: 12, 24, 36, 48, ...
Step 5: Look for the smallest number that appears in both lists of multiples. The multiples of 8 are 8, 16, 24, ... and the multiples of 12 are 12, 24, ...
Step 6: The smallest number that is in both lists is 24.
Step 7: Therefore, the smallest number that is divisible by both 8 and 12 is 24.