If a number is divisible by both 6 and 8, which of the following must it also be divisible by?

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Q: If a number is divisible by both 6 and 8, which of the following must it also be divisible by?

Solution: The least common multiple of 6 and 8 is 24, so any number divisible by both must also be divisible by 24.

Steps: 6

Step 1: Understand what it means for a number to be divisible by another number. A number is divisible by another if you can divide them without leaving a remainder.
Step 2: Identify the numbers we are working with: 6 and 8.
Step 3: Find the least common multiple (LCM) of 6 and 8. The LCM is the smallest number that both 6 and 8 can divide into evenly.
Step 4: To find the LCM of 6 and 8, list the multiples of each number: Multiples of 6 are 6, 12, 18, 24, 30, ... and multiples of 8 are 8, 16, 24, 32, ...
Step 5: Look for the smallest number that appears in both lists of multiples. The smallest number is 24.
Step 6: Conclude that if a number is divisible by both 6 and 8, it must also be divisible by their LCM, which is 24.