If a foundation has a width of 2 m and is subjected to a load of 400 kN, what is the bearing pressure?
Practice Questions
1 question
Q1
If a foundation has a width of 2 m and is subjected to a load of 400 kN, what is the bearing pressure?
100 kPa
200 kPa
300 kPa
400 kPa
Bearing pressure (q) is calculated as q = Load / Area. The area of the foundation is 2 m * 1 m = 2 m². Therefore, q = 400 kN / 2 m² = 200 kPa.
Questions & Step-by-step Solutions
1 item
Q
Q: If a foundation has a width of 2 m and is subjected to a load of 400 kN, what is the bearing pressure?
Solution: Bearing pressure (q) is calculated as q = Load / Area. The area of the foundation is 2 m * 1 m = 2 m². Therefore, q = 400 kN / 2 m² = 200 kPa.
Steps: 7
Step 1: Identify the load applied to the foundation, which is 400 kN.
Step 2: Identify the width of the foundation, which is 2 m.
Step 3: Assume the length of the foundation is 1 m (since it's not given, we can use this for calculation).
Step 4: Calculate the area of the foundation using the formula: Area = Width * Length. So, Area = 2 m * 1 m = 2 m².
Step 5: Use the formula for bearing pressure: q = Load / Area. Here, q = 400 kN / 2 m².
Step 6: Perform the calculation: 400 kN / 2 m² = 200 kPa.
Step 7: Conclude that the bearing pressure is 200 kPa.
