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If a charge of +1 µC is placed in an electric field of 2000 N/C, what is the for
If a charge of +1 µC is placed in an electric field of 2000 N/C, what is the force acting on the charge? (2021)
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Q1
If a charge of +1 µC is placed in an electric field of 2000 N/C, what is the force acting on the charge? (2021)
0.002 N
0.2 N
2 N
20 N
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Force F = qE = (1 × 10^-6 C) * (2000 N/C) = 0.002 N.
Questions & Step-by-step Solutions
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Q
Q: If a charge of +1 µC is placed in an electric field of 2000 N/C, what is the force acting on the charge? (2021)
Solution:
Force F = qE = (1 × 10^-6 C) * (2000 N/C) = 0.002 N.
Steps: 5
Show Steps
Step 1: Identify the charge value. The charge given is +1 µC (microcoulomb). Convert this to coulombs: 1 µC = 1 × 10^-6 C.
Step 2: Identify the electric field strength. The electric field strength given is 2000 N/C.
Step 3: Use the formula for force in an electric field, which is F = qE, where F is the force, q is the charge, and E is the electric field strength.
Step 4: Substitute the values into the formula: F = (1 × 10^-6 C) * (2000 N/C).
Step 5: Calculate the force: F = 1 × 10^-6 * 2000 = 0.002 N.
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