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If a binary search is performed on an array of 32 elements, how many iterations
If a binary search is performed on an array of 32 elements, how many iterations will it take in the worst case?
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Q1
If a binary search is performed on an array of 32 elements, how many iterations will it take in the worst case?
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The worst-case number of iterations is log2(32) = 5.
Questions & Step-by-step Solutions
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Q: If a binary search is performed on an array of 32 elements, how many iterations will it take in the worst case?
Solution:
The worst-case number of iterations is log2(32) = 5.
Steps: 6
Show Steps
Step 1: Understand that a binary search works by repeatedly dividing the array in half.
Step 2: Know that the maximum number of times you can divide an array of size n is related to the logarithm base 2 of n.
Step 3: For this question, the size of the array is 32.
Step 4: Calculate log2(32). This means you want to find out how many times you can divide 32 by 2 until you reach 1.
Step 5: Since 32 is 2 raised to the power of 5 (because 2^5 = 32), log2(32) equals 5.
Step 6: Therefore, in the worst case, it will take 5 iterations to find the target element or determine it is not in the array.
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