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If a 9V battery is connected to a 3Ω resistor, what is the energy consumed in 10
If a 9V battery is connected to a 3Ω resistor, what is the energy consumed in 10 seconds? (2023)
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Practice Questions
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If a 9V battery is connected to a 3Ω resistor, what is the energy consumed in 10 seconds? (2023)
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Power (P) = V²/R = 9²/3 = 27W. Energy (E) = P * t = 27W * 10s = 270J.
Questions & Step-by-step Solutions
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Q
Q: If a 9V battery is connected to a 3Ω resistor, what is the energy consumed in 10 seconds? (2023)
Solution:
Power (P) = V²/R = 9²/3 = 27W. Energy (E) = P * t = 27W * 10s = 270J.
Steps: 10
Show Steps
Step 1: Identify the voltage of the battery, which is 9V.
Step 2: Identify the resistance of the resistor, which is 3Ω.
Step 3: Use the formula for power (P) which is P = V²/R.
Step 4: Substitute the values into the formula: P = 9²/3.
Step 5: Calculate 9², which is 81.
Step 6: Divide 81 by 3 to find the power: 81/3 = 27W.
Step 7: Identify the time duration, which is 10 seconds.
Step 8: Use the formula for energy (E) which is E = P * t.
Step 9: Substitute the power and time into the formula: E = 27W * 10s.
Step 10: Calculate the energy: 27 * 10 = 270J.
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