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If a 2 kg object is lifted to a height of 5 m, what is the work done against gra
If a 2 kg object is lifted to a height of 5 m, what is the work done against gravity? (g = 10 m/s²) (2019)
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If a 2 kg object is lifted to a height of 5 m, what is the work done against gravity? (g = 10 m/s²) (2019)
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Work Done = mgh = 2 kg * 10 m/s² * 5 m = 100 J
Questions & Step-by-step Solutions
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Q
Q: If a 2 kg object is lifted to a height of 5 m, what is the work done against gravity? (g = 10 m/s²) (2019)
Solution:
Work Done = mgh = 2 kg * 10 m/s² * 5 m = 100 J
Steps: 7
Show Steps
Step 1: Identify the mass of the object. In this case, the mass (m) is 2 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 5 m.
Step 3: Identify the acceleration due to gravity. In this problem, g is given as 10 m/s².
Step 4: Use the formula for work done against gravity, which is Work Done = m * g * h.
Step 5: Substitute the values into the formula: Work Done = 2 kg * 10 m/s² * 5 m.
Step 6: Calculate the result: 2 * 10 * 5 = 100.
Step 7: Conclude that the work done against gravity is 100 Joules (J).
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