If 100 g of glucose (C6H12O6) is dissolved in 1 L of solution, what is the molarity of the solution? (Molar mass of glucose = 180 g/mol)

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Q: If 100 g of glucose (C6H12O6) is dissolved in 1 L of solution, what is the molarity of the solution? (Molar mass of glucose = 180 g/mol)

Solution: Moles of glucose = 100 g / 180 g/mol = 0.556 moles. Molarity = moles of solute / liters of solution = 0.556 moles / 1 L = 0.56 M.

Steps: 8

Step 1: Identify the mass of glucose you have, which is 100 grams.
Step 2: Find the molar mass of glucose, which is given as 180 grams per mole.
Step 3: Calculate the number of moles of glucose using the formula: moles = mass (g) / molar mass (g/mol). So, moles of glucose = 100 g / 180 g/mol.
Step 4: Perform the calculation: 100 divided by 180 equals approximately 0.556 moles.
Step 5: Identify the volume of the solution, which is 1 liter.
Step 6: Calculate the molarity using the formula: molarity = moles of solute / liters of solution. So, molarity = 0.556 moles / 1 L.
Step 7: Perform the calculation: 0.556 divided by 1 equals 0.556 M.
Step 8: Round the answer to two decimal places, which gives you 0.56 M.