If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (2023)

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Question: If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (2023)

Options:

4.76%
5.00%
10.00%
20.00%

Correct Answer: 5.00%

Exam Year: 2023

Solution:

Mass percent = (mass of solute / mass of solution) × 100. Mass of solution = 10 g + 200 g = 210 g. Mass percent = (10 g / 210 g) × 100 = 4.76%.

Practice Questions

1 question

If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (2023)

4.76%
5.00%
10.00%
20.00%

Questions & Step-by-step Solutions

1 item

Q: If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (2023)

Solution: Mass percent = (mass of solute / mass of solution) × 100. Mass of solution = 10 g + 200 g = 210 g. Mass percent = (10 g / 210 g) × 100 = 4.76%.

Steps: 6

Step 1: Identify the mass of the solute (sugar) which is 10 g.
Step 2: Identify the mass of the solvent (water) which is 200 g.
Step 3: Calculate the total mass of the solution by adding the mass of the solute and the mass of the solvent: 10 g + 200 g = 210 g.
Step 4: Use the mass percent formula: Mass percent = (mass of solute / mass of solution) × 100.
Step 5: Substitute the values into the formula: Mass percent = (10 g / 210 g) × 100.
Step 6: Calculate the mass percent: 10 g / 210 g = 0.047619, then multiply by 100 to get 4.76%.

If 10 g of sugar (C12H22O11) is dissolved in 200 g of water, what is the mass percent of the solution? (2023)

Description

Practice Questions

Questions & Step-by-step Solutions

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