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For the quadratic equation x^2 + 6x + 9 = 0, what type of roots does it have? (2
For the quadratic equation x^2 + 6x + 9 = 0, what type of roots does it have? (2019)
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For the quadratic equation x^2 + 6x + 9 = 0, what type of roots does it have? (2019)
Real and distinct
Real and equal
Complex
None of the above
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The discriminant D = 6^2 - 4*1*9 = 0, indicating real and equal roots.
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Q: For the quadratic equation x^2 + 6x + 9 = 0, what type of roots does it have? (2019)
Solution:
The discriminant D = 6^2 - 4*1*9 = 0, indicating real and equal roots.
Steps: 7
Show Steps
Step 1: Identify the coefficients in the quadratic equation x^2 + 6x + 9 = 0. Here, a = 1, b = 6, and c = 9.
Step 2: Use the formula for the discriminant D = b^2 - 4ac.
Step 3: Substitute the values of a, b, and c into the formula: D = 6^2 - 4*1*9.
Step 4: Calculate 6^2, which is 36.
Step 5: Calculate 4*1*9, which is 36.
Step 6: Now, subtract the two results: D = 36 - 36 = 0.
Step 7: Interpret the result: Since the discriminant D = 0, this means the quadratic equation has real and equal roots.
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