For a first-order reaction, if the half-life is 10 minutes, what is the rate constant?

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0.0693 min^-1
0.1 min^-1
0.693 min^-1
0.5 min^-1

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Q: For a first-order reaction, if the half-life is 10 minutes, what is the rate constant?

Solution: The half-life (t1/2) of a first-order reaction is given by t1/2 = 0.693/k. Rearranging gives k = 0.693/t1/2 = 0.693/10 min = 0.0693 min^-1.

Steps: 6

Step 1: Understand that we are dealing with a first-order reaction.
Step 2: Know that the formula for the half-life (t1/2) of a first-order reaction is t1/2 = 0.693/k.
Step 3: Identify the given half-life, which is 10 minutes.
Step 4: Rearrange the formula to solve for the rate constant (k): k = 0.693/t1/2.
Step 5: Substitute the half-life value into the rearranged formula: k = 0.693/10 min.
Step 6: Calculate the value: k = 0.0693 min^-1.

For a first-order reaction, if the half-life is 10 minutes, what is the rate constant?

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